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3 years ago

WORTH 100 POINTS

Chemistry

1 answer:

hjlf3 years ago

5 0

Answer:

When 0.250 moles of a gas is placed in a container at 25 °C, it exerts a pressure of 700 mm Hg.

Explanation:

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What is 1.0 x 10^4 L in nL?

Vlada [557]

Answer:

= 10000000000000 Nanoliters

Explanation:

1.0 x (10^4) L =

10 000 L

10 000L converted into Nanoliters

= 10000000000000 Nanoliters

Hope this helps

6 0

3 years ago

Chlorine gas can be prepared in the laboratory by the reaction of hydrochloric acid with manganese(IV) oxide. 4 HCl ( aq ) + MnO

Leno4ka [110]

Answer:

1. HCl is the limiting reactant.

2. The theoretical yield of Cl2 is 23.197g

3. The Actual yield 19.787g

Explanation:

4HCl + MnO2 —> MnCl2 + 2H2O + Cl2

First let us calculate the number of mole of HCl and MnO2.

Molar Mass of HCl = 1 + 35.5 = 36.5g/mol

Mass of HCl = 47.7g

Number of mole = Mass /Molar Mass

Number of mole of HCl = 47.7/36.5 = 1.31mole

Molar Mass of MnO2 = 35 + (2x16) = 35 + 32 = 67g/mol

Mass of MnO2 = 40.5g

Number of mole = Mass /Molar Mass

Number of mole of MnO2 = 40.5/67 = 0.60mole

From equation,

4moles of HCl required 1mole of MnO2. Now let us consider the following:

4moles HCl require 1mole MnO2. Therefore 0.31mol of HCl will require = 0.31/4 = 0.0775mole of MnO2. This amount is little compared to the amount of MnO2 ( i.e 0.60mol) calculated. Therefore, HCl is the limiting reactant.

2. 4HCl + MnO2 —> MnCl2 + 2H2O + Cl2

Molar Mass of HCl = 36.5g/mol

Mass of HCl from the balanced equation = 4 x 36.5 = 146g

Molar Mass of Cl2 = 2 x 35.5 = 71g/mol

From the equation,

146g of HCl produced 71g of Cl2.

Therefore, 47.7g of HCl will produce = (47.7x 71)/146 = 23.197g of Cl2.

The theoretical yield of Cl2 is 23.197g

3. %yield = 85.3%

Theoretical yield = 23.197g

Actual yield =?

%yield = Actual yield /Theoretical yield

Actual yield = %yield x theoretical yield

Actual yield = 85.3% x 23.197g = (85.3/100) x 23.197 = 19.787g

5 0

3 years ago

A 47.1 g sample of a metal is heated to 99.0°C and then placed in a calorimeter containing 120.0 g of water (c = 4.18 J/g°C) at

wlad13 [49]

Answer : The metal used was iron (the specific heat capacity is $0.44J/g^oC$ ).

Explanation :

In this problem we assumed that heat given by the hot body is equal to the heat taken by the cold body.

$q_1=-q_2$

$m_1\times c_1\times (T_f-T_1)=-m_2\times c_2\times (T_f-T_2)$

where,

$C_1$ = specific heat of metal = ?

$C_1$ = specific heat of water = $4.18J/g^oC$

$m_1$ = mass of metal = 47.1 g

$m_2$ = mass of water = 120 g

$T_f$ = final temperature of water = $24.5^oC$

$T_1$ = initial temperature of metal = $99^oC$

$T_2$ = initial temperature of water = $21.4^oC$

Now put all the given values in the above formula, we get

$47.1g\times c_1\times (24.5-99)^oC=-120g\times 4.18J/g^oC\times (24.5-21.4)^oC$

$c_1=0.44J/g^oC$

Form the value of specific heat of metal, we conclude that the metal used in this was iron.

Therefore, the metal used was iron (the specific heat capacity is $0.44J/g^oC$ ).

3 0

3 years ago

Solid

sp2606 [1]

Sorry I’m not there yet

8 0

3 years ago

Atoms of the element sodium “want” to give up an electron<br> because sodium atoms

Svetlanka [38]

Sodium want to give up an electron and "will always want to give up an electron* because less energy is needed to remove the one valence electron of sodium in order to have an octet configuration. This is the reason why sodium and other alkali metals form positive ions so easily.

<h2>Case study</h2>

For instance: In forming an ionic bond, the sodium atom, which is electropositive, loses its valence electron to chlorine. The resulting sodium ion has the same electron configuration as neon (1s2 2s22p6). It has a +1 charge, because there are 11 protons in the nucleus, but only 10 electrons around the nucleus of the ion

Learn more about sodium:

brainly.com/question/25832904

3 0

2 years ago

Read 2 more answers