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Lady_Fox [76]
3 years ago
6

WORTH 100 POINTS

Chemistry
1 answer:
hjlf3 years ago
5 0

Answer:

When 0.250 moles of a gas is placed in a container at 25 °C, it exerts a pressure of 700 mm Hg.

Explanation:

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How many grams of solute are needed to make 37.5 mL of 0.750 M KI solution? Round to three significant digits.
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4.648 gm of solute is needed to make 37.5 mL of 0.750 M KI solution.

Solution:  

We will start with the Molarity  

\text { Molarity }=\text { Mole of solute } \div \text { liter of solution }

Also we know 1000 ml = 1 L

Therefore 37.5 ml by 1000ml we obtained 0.0375L  

Equation for solving mole of solute

\text { Mole of solute }=\text { Molarity } \times \text { Liters of solution }

Now, multiply 0.750M by 0.0375

Substitute the known values in the above equation we get

0.750 \times 0.0375=0.0281

Also we know that Molar mass of KI is 166 g/mol

So divide the molar mass value to get the no of grams.

0.028 \times 166=4.648

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