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UNO [17]
3 years ago
10

Robin throws a penny up in the air. If the penny's initial velocity is 1.0m/s[up] and it is launched from a height of 1.5 m, wha

t is the maximum height of the penny above the ground?
Physics
1 answer:
Irina-Kira [14]3 years ago
6 0

Answer:

1.55m

Explanation:

The formula for calculating the maximum height is expressed as;

H = u²/2g

u is the initial velocity

g is the acceleration due to gravity

Substitute

H = 1²/2(9.8)

H = 1/19.6

H = 0.051m

Since it is launched form a height of 1.5m, the height above the ground will be 1.5+0.051 = 1.55m

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During nuclear fission and fusion, matter that seems to disappear is actually converted into
iris [78.8K]

Answer:

Energy (I need one more brainlist can i has?)

Explanation:

- Nuclear fusion occurs when two light nuclei fuse together into a heavier nucleus

- Nuclear fission occurs when a heavy, unstable nucleus breaks apart into two or more lighter nuclei

In both processes, the mass of the products is always smaller than the mass of the initial nuclei. This means that part of the initial mass has been converted into something else: into energy, which is released in the process.

The amount of energy released in the process can be calculated by using the famous Einstein's equivalence:

where m is the difference between the mass of the product and the initial mass of the nuclei, and c is the speed of light.

8 0
3 years ago
Read 2 more answers
What is the centripetal force acting on a 1.5 kg mass moving in a circular path with a centripetal
zloy xaker [14]

The centripetal force acting on a 1.5 kg mass moving in a circular path is 27N

A centripetal force is a net force acting on an object in order to maintain the object's movement in a circular motion.

According  to Newton's first law, it states an object will continue to proceed its movement in a straight line unless acted upon by an external force.

The centripetal force is the external force at work here and  It's the net force that propels the object in a circular motion.

Using the formula for calculating centripetal force:

\mathbf{F_c = mass (m) \times acceleration (a)}

\mathbf{F_c = 1.5 \ kg \times18 \ m/s^2}

\mathbf{F_c = 27 \ N}

Learn more about centripetal force here:

brainly.com/question/11324711?referrer=searchResults

8 0
3 years ago
A man is sitting on a chair with wheels. He grabs a 2.1 kg book from the desk and throws
geniusboy [140]

The speed of the man and the chair after the book is thrown is 0.2 m/s.

The given parameters:

  • <em>mass of the book, m₁ = 2.1 kg</em>
  • <em>speed of the book, u₁ = 7.2 m/s</em>
  • <em>mass of the man, M = 70 kg</em>
  • <em>mass of the book, m = 9.2 kg</em>

<em />

The total mass of the man and the book is calculated as follows;

m₂ = 70 kg + 9.2 kg

m₂ = 79.2 kg

The speed of the man and the chair after the book is thrown is determined by applying the principle of conservation of linear momentum;

m_1 u_1 = m_2u_2\\\\u_2 = \frac{m_1u_1}{m_2} \\\\u_2 = \frac{2.1 \times 7.2}{79.2} \\\\u_2 = 0.2 \ m/s

Thus, the speed of the man and the chair after the book is thrown is 0.2 m/s.

Learn more about conservation of linear momentum here: brainly.com/question/7538238

8 0
3 years ago
hovering mosquito is hit by a raindrop that is 45 times as massive and falling at 8.1 m/s , a typical raindrop speed. How fast i
Y_Kistochka [10]

Answer:

7.92 m/s

Explanation:

m_1 = Mass of raindrop = 45m_2

m_2 = Mass of mosquito

u_1 = Initial Velocity of raindrop = 8.1 m/s

u_2 = Initial Velocity of mosquito = 0 m/s

v = Velocity of center of mass

For elastic collision

m_1u_1 + m_2u_2 =(m_1 + m_2)v\\\Rightarrow v=\frac{m_1u_1 + m_2u_2}{m_1 + m_2}\\\Rightarrow v=\frac{45m_2\times 8.1 + m_2\times 0}{45m_2 + m_2}\\\Rightarrow v=\frac{364.5m_2}{46m_2}\\\Rightarrow v=7.92\ m/s

Hence, the velocity of the attached mosquito, falling immediately afterward is 7.92 m/s

4 0
3 years ago
A beach ball with a volume of 5,000 cm3 is pushed underwater. What is the magnitude of the buoyant force pushing upwards? The de
Kobotan [32]
<h2>Hello!</h2>

The answer is:

The buoyant force is equal to 49N.

<h2>Why?</h2>

The buoyant force is the force that pushes upwards and object when it's submerged in water, this force is always trying to move the object to the surface of the liquid or water.  We must consider that the volume of water or liquid displaced is equal to the volume of the submerged object.

We can calculate the buoyant force using the following formula:

F_{B}=Density*VolumeDisplaced*GravityAcceleration

Where,

Density is the density of the water or liquid.

Volume displaced is equal to the volume of the submerged object.

Gravity acceleration is the acceleration due to gravity.

So, from the statement we know that:

VolumeDisplaced=BeachBallVolume=5000cm^{3}\\\\Density=1\frac{gram}{cm^{3} }=\frac{0.001kg}{cm^{3} }\\\\g=9.8\frac{m}{s^{2} }

Now, substituting and calculating we have:

F_{B}=Density*VolumeDisplaced*GravityAcceleration

F_{B}=0.001\frac{kg}{cm^{3}*} *5000cm^{3}*9.8\frac{m}{s^{2} }

F_{B}=0.001\frac{kg}{cm^{3}*} *5000cm^{3}*9.8\frac{m}{s^{2} }

F_{B}=49\frac{Kg.m}{s^{2}}=49N

Hence, we have that the correct answer is:

The buoyant force is equal to 49N.

Have a nice day!

7 0
4 years ago
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