The elastic potential of a spring can be calculated using the formula
E = (1/2) k x²
where are given that
k = 120 N/m
the stretched length is
x = 0.02 m
The elastic potential is
E = (1/2) (120 N/m) (0.02 m)²
E = 0.024 N-m<span />
Answer:
Explanation:
There are a couple of ways you could do this.
The easiest is to use E*R1/(R1 + R2)
- E = 10 volts
- R1 = 590 ohms
- R2 = 840 ohms
So the result would be
E_590 = 10 * 590/(590 + 840)
E_590 = 10 * 590/ (1430)
E_590 = 4.13 volts rounded.
You could do this a slightly longer way.
R = 1430 (total ohms in series.
E = 10 volts
I = ???
I = E/R
I = 10 / 1430
I = 0.00699
Now use this current to figure out the voltage drop.
E = I * R
I = 0.00699 amps
R = 590 ohms
E = 0.00699 * 590
E = 4.13 volts
Pick the way of doing it you like best.
Answer: D. They are the coldest stars.
Explanation:
An opera singer breaks a thin glass with only the use of her high frequency voice
H = mc∆T
where, H=heat energy
c = SHC
H = 2*921*(40-20)
H = 36840J
H = 36.84KJ
The energy transferred to it is 36.84KJ