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Andrew [12]
3 years ago
9

True or false Variables are those factors that can be changed in an experiment

Physics
1 answer:
tekilochka [14]3 years ago
6 0
True

Variables is changing. It is any factor, trait or condition that can exist in differing amounts or types. An experiment has three types: Independent, Dependent and Controlled.
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Complete the sentences below correctly. Stunt Car A and Stunt Car B are identical cars with the same mass of 48.9 kg. They are b
ivann1987 [24]

Answer:

Stunt Car A experiences a large force over a short period of time. Stunt Car B experiences a small force over a long period of time. Because of the force experienced by Stunt Car A, it will sustain more damage than Stunt Car B.

Explanation:

Both cars have the same mass and velocity, therefore they have the same momentum. During the collision, the total momentum of the car A and brick wall is conserved as well as the total momentum of the car B and the pile of leaves.

However, if we are to investigate the damage on each car, we should look at the cars not the whole system. So, the momentum difference between the cars gives us the impulse that the car felt.

\vec{J} = \Delta \vec{P}\\\vec{F}\Delta t = \vec{P}_2 - \vec{P}_1

Since the Car A will crash the wall quicker than the other car crashes through the pile of leaves,

\Delta t_1 < \Delta t_2

which gives us

F_1 > F_2

4 0
3 years ago
How do ballerinas take advantage of conservation of momentum to turn?.
mars1129 [50]
The ballerinas takes advantage of the moment of interia by not stretching her hands out etc. and by doing so decreasing the moment of interia and therefore a smaller torque is produced to rotate at a faster rate.
5 0
2 years ago
A proton is moved from the negative to the positive plate of a parallel-plate arrangement. The plates are 1.50 cm apart, and the
Nana76 [90]

(a) The proton’s potential energy change is 3.6 x 10⁻¹⁸ J.

(b) The potential difference between the negative plate and a point midway between the plates is 11.25 V.

(c) The speed of the proton just before it hits the negative plate is 6.57 x 10⁴ m/s.

<h3>Potential energy of the proton</h3>

U = qΔV

where;

  • q is charge of the proton
  • ΔV is potential difference

U = q(Ed)

U = (1.6 x 10⁻¹⁹)(1500 x 1.5 x 10⁻²)

U = 3.6 x 10⁻¹⁸ J

<h3>Potential difference between the negative plate and a point midway</h3>

ΔV = E(0.5d)

ΔV = 0.5Ed

ΔV = 0.5 (1500)(1.5 x 10⁻²)

ΔV = 11.25 V

<h3>Speed of the proton </h3>

U = ¹/₂mv²

U = mv²

v² = 2U/m

where;

  • m is mass of proton = 1.67 x 10⁻²⁷ kg

v² = (2 x 3.6 x 10⁻¹⁸) / ( 1.67 x 10⁻²⁷)

v² = 4.311 x 10⁹

v = √(4.311 x 10⁹)

v = 6.57 x 10⁴ m/s

Thus, the proton’s potential energy change is 3.6 x 10⁻¹⁸ J.

The potential difference between the negative plate and a point midway between the plates is 11.25 V.

The speed of the proton just before it hits the negative plate is 6.57 x 10⁴ m/s.

Learn more about potential difference here: brainly.com/question/24142403

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4 0
2 years ago
A white pool ball of mass 1.0 kg moving at 10 m/s collides with
solniwko [45]

The velocity of the red ball after the collision is 5.8 m/s

Explanation:

In absence of external forces on the system, we can apply the principle of conservation of momentum. The total momentum of the system must be conserved before and after the collision, so we can write:

p_i = p_f\\m_1 u_1 + m_2 u_2 = m_1 v_1 + m_2 v_2

where:

m_1 = 1.0 kg is the mass of the pool ball

u_1 = 10 m/s is the initial velocity of the pool ball

v_1 = 3.0 m/s is the final velocity of the pool ball

m_2 = 1.2 kg is the mass of the red ball

u_2 = 0 is the initial velocity of the red ball

v_2 is the final velocity of the red ball

Solving the equation for v2, we find the final velocity of the red ball after the collision:

v_2 = \frac{m_1 u_1-m_1v_1}{m_2}=\frac{(1.0)(10)-(1.0)(3.0)}{1.2}=5.8 m/s

Learn more about collisions:

brainly.com/question/13966693#

brainly.com/question/6439920

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7 0
3 years ago
Right an essay about 250-200 words about water
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Answer:250-200l Water

Explanation:

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3 years ago
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