The measurement of the wave trough
Answer:
4 A
Explanation:
Firstly we need to calculate the equivalent resistance. Since, two resistors of 6 connected in parallel, so equivalent resistance will be given by,
1/R = 1/R1 + 1/R2
1/R = (1/6 + 1/6) Ω
1/R = (1 + 1)/6 Ω
1/R = 2/6 Ω
R = 6/2 Ω
<u>R = 3 Ω</u>
We know that,
V = IR
- <em>V</em> denotes p.d (12V)
- <em>I</em> denotes current
- <em>R</em> denotes resistance (3 Ω)
12 = I × 3
12 ÷ 3 = I
<u>4 Ampere = I</u>
Answer:
The period of 6/7 seconds or 0.857 seconds.
Explanation:
The period of any given trigonometric function is given by:
In this function b is
So, the period for the given function is calculated as follows: