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andre [41]
3 years ago
5

What is the volume of 1.56 kg of a compound whose molar mass is 81.86 g/mole and whose density is 41.2 g/ml?

Chemistry
1 answer:
hjlf3 years ago
7 0

Answer:

v = 37.9 ml

Explanation:

Given data:

Mass of compound = 1.56 kg

Density = 41.2 g/ml

Volume of compound = ?

Solution:

First of all we will convert the mass into g.

1.56 ×1000 = 1560 g

Formula:

D=m/v

D= density

m=mass

V=volume

v = m/d

v =  1560 g / 41.2 g/ml

v = 37.9 ml

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“Electrons” An atom is neutral because it has the same number of positive charges protons as it has electrons.
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3 years ago
Calculate the relative rate of effusion for the orange to blue spheres. The root-mean-square speed for the orange spheres is 565
Tanzania [10]

Answer:

Relative rate of effusion for the orange to blue spheres = 1.531

Explanation:

Rate of effusion of Orange / Rate of effusion of blue = [Mblue / Morange]^1/2

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Vorange / Vblue = [ Mblue / Morange]^1/2

Rate of effusion of Orange / Rate of effusion of blue = 565/ 369 = 1.531

5 0
3 years ago
Read 2 more answers
What is cis-3-Hexene?
valentinak56 [21]

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7 0
3 years ago
Butane gas reacts with oxygen gas to give carbon dioxide gas and water vapor (gas). If you mix butane and oxygen in the correct
Fittoniya [83]

Answer:

118.776 mmHg

Explanation:

The equation of the reaction is;

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Now the mole ratio  according to the balanced reaction equation is;

1 : 6.5 : 4 : 5

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Mole fraction of water vapour = 5/16.5 = 0.303

We also know that;

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7 0
3 years ago
Complete these structures by adding electron dots as needed.
LiRa [457]
This is hard to show but here is how you would determine these. NOTE each dot is an electron. 
<span>Question 1) </span>
<span>F-H </span>
<span>1) determine the valance electrons for each. F has 7 and H has 1 </span>
<span>2) one electron from both F and H form the bond "-" which means that you still have 6 electrons to place around F and none to place around H. Place the 6 in sets of 2 around the F </span>
<span>.. </span>
<span>F-H </span>
<span>¨ </span>
<span>Question 2) </span>

<span>2) H-O-H </span>
<span>H has 1 valence electron minus 1 used in the bond to O = 0 electrons to place </span>
<span>H has 1 valence electron minus 1 used in the bond to O = 0 electrons to place </span>
<span>O has 6 valence electrons minus 2 used in the bonds to the H's = 4 electrons to place </span>

<span>H-O-H: place two dots above and below the oxygen </span>

<span>Question 3) </span>
<span>3) O=N----H : NOTE: a double bond requires O and N to share two of their electrons each </span>
<span>O has 6 valence electrons minus 2 used in the bonds to N = 4 electrons to place </span>
<span>N has 5 valence electrons minus 3 used in the bonds to O and H = 2 electrons to place </span>
<span>H has 1 valence electron minus 1 used in the bond to N = 0 electrons to place </span>
<span>place the 2 dots on top and bottom of oxygen. </span>
<span>place 2 above the N </span>
7 0
3 years ago
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