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3 years ago

3

What is the domain of the function shown in the graph below

1 answer:

murzikaleks [220]3 years ago

3 0

Answer:

Domain: (-∞, -7) ∪ (-7, ∞)

Step-by-step explanation:

There is a vertical asymptote at x = -7, so the answer would be all real numbers except for when x= -7

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Please help these problems are hard

Pachacha [2.7K]

Answer:

2/5

Step-by-step explanation:

For the denominator you are looking for the total number of options, and in this case it is 10. Then for the numerator you are looking for what the question is asking for, in this case, it is looking for letters n to q. n, o, p and q are what you are looking for. With this information you will get 4/10 and simplified, 2/5

6 0

4 years ago

A new catalyst is being investigated for use in the production of a plastic chemical. Ten batches of the chemical are produced.

zzz [600]

Answer:

$CI=(66.54,78.46)$

Step-by-step explanation:

Given : A new catalyst is being investigated for use in the production of a plastic chemical. Ten batches of the chemical are produced. The mean yield of the 10 batches is 72.5% and the standard deviation is 5.8%. Assume the yields are independent and approximately normally distributed.

To find : A 99% confidence interval for the mean yield when the new catalyst is used ?

Solution :

Let X be the yield of the batches.

We have given, n=10 , $\bar{X}=72.5\%$ , s=5.8%

Since the size of the sample is small.

We will use the student's t statistic to construct a 995 confidence interval.

$\bar X\pm t_{n-1,\frac{\alpha}{2}}\frac{s}{\sqrt n}$

From the t-table with 9 degree of freedom for $\frac{\alpha}{2}=0.005$

$t_{n-1,\frac{\alpha}{2}}=t_{9,0.005}$

$t_{n-1,\frac{\alpha}{2}}=3.250$

The 99% confidence interval is given by,

$CI=72.5 \pm 3.25\frac{5.8}{\sqrt{10}}$

$CI=72.5 \pm 5.96$

$CI=(72.5+5.96),(72.5-5.96)$

$CI=(66.54,78.46)$

8 0

3 years ago

On the day after my birthday this year, I can truthfully say: "The day after tomorrow is Monday". On which day is my birthday?

andriy [413]

Answer: Friday

Step-by-step explanation:

5 0

2 years ago

Evaluate each expression when n = 4 and b = 7

alexgriva [62]

Answer:

1. 5 2. 31 3. 55

Step-by-step explanation:

1. 2(4)-3=8-3=5

2. 4(7)+3=28+3=31

3. 3(4)+8(7)-13=12+56-13=56-1=55

4 0

3 years ago

Read 2 more answers

Each of 16 students measured the circumference of a tennis ball by four different methods, which were: A: Estimate the circumfer

almond37 [142]

Answer:

Following are the solution to the given equation:

Step-by-step explanation:

Please find the complete question in the attachment file.

In point a:

$\to \mu=\frac{\sum xi}{n}$

$=22.8$

$\to \sigma=\sqrt{\frac{\sum (xi-\mu)^2}{n-1}}$

$=\sqrt{\frac{119.18}{16-1}}\\\\ =\sqrt{\frac{119.18}{15}}\\\\ = \sqrt{7.94533333}\\\\=2.8187$

In point b:

$\to \mu=\frac{\sum xi}{n}$

$=20.6875$

$\to \sigma=\sqrt{\frac{\sum (xi-\mu)^2}{n-1}}$

$=\sqrt{\frac{26.3375}{16-1}}\\\\=\sqrt{\frac{26.3375}{15}}\\\\ =\sqrt{1.75583333}\\\\ =1.3251$

In point c:

$\to \mu=\frac{\sum xi}{n}$

$=21$

$\to \sigma=\sqrt{\frac{\sum (xi-\mu)^2}{n-1}}$

$=\sqrt{\frac{2.62}{16-1}}\\\\ =\sqrt{\frac{2.62}{15}} \\\\= \sqrt{0.174666667}\\\\=0.4179$

In point d:

$\to \mu=\frac{\sum xi}{n}$

$=20.8375$

$\to \sigma=\sqrt{\frac{\sum (xi-\mu)^2}{n-1}}$

$=\sqrt{\frac{8.2975}{16-1}}\\\\ =\sqrt{\frac{8.2975}{15}} \\\\ =\sqrt{0.553166667} \\\\ =0.7438$

6 0

3 years ago