Answer:
See answer
Explanation:
The area of the circular loop is given by:
![A = \pi r^2](https://tex.z-dn.net/?f=A%20%3D%20%5Cpi%20r%5E2)
The magnetic flux is given by:
![\phi = \int \vec{B} \cdot d\vec{A}](https://tex.z-dn.net/?f=%5Cphi%20%3D%20%5Cint%20%5Cvec%7BB%7D%20%5Ccdot%20d%5Cvec%7BA%7D)
is parallel to
and
is constant in magnitude and direction therefore:
![\phi = \int \vec{B} \cdot d\vec{A}= \int BdAcos(0)= B\int dA= B*(\pi r^2)= \pi Br^2](https://tex.z-dn.net/?f=%5Cphi%20%3D%20%5Cint%20%5Cvec%7BB%7D%20%5Ccdot%20d%5Cvec%7BA%7D%3D%20%5Cint%20BdAcos%280%29%3D%20B%5Cint%20dA%3D%20B%2A%28%5Cpi%20r%5E2%29%3D%20%5Cpi%20Br%5E2)
Part A)
initially the flux is ![\phi =\pi B r^2](https://tex.z-dn.net/?f=%5Cphi%20%3D%5Cpi%20B%20r%5E2)
after the interval
the flux is
![\phi = 0](https://tex.z-dn.net/?f=%5Cphi%20%3D%200)
now, the EMF is defined as:
,
if we consider
very small then we can re-write it as:
![\epsilon =- \frac{\Delta \phi}{\Delta t}](https://tex.z-dn.net/?f=%5Cepsilon%20%3D-%20%5Cfrac%7B%5CDelta%20%5Cphi%7D%7B%5CDelta%20t%7D)
then:
![\epsilon =- \frac{-0.12}{0.0024} = 50 [V]](https://tex.z-dn.net/?f=%5Cepsilon%20%3D-%20%5Cfrac%7B-0.12%7D%7B0.0024%7D%20%3D%2050%20%5BV%5D)
Part B)
When looked down from above, the current flows counter clockwise, according to the right hand rule, if you place your thumb upwards (the direction of the magnetic field) and close your fingers, then the current will flow in the direction of your fingers.
I say it is false that is the correct answer
The magnitude of your displacement can be less than your distance traveled And The magnitude of your displacement can be equal to your distance traveled.
Magnitude in physics is simply described as "distance or quantity." It shows the size or direction that an object moves in either an absolute or relative sense. A force's magnitude is defined as the total amount of forces operating on an item. The strength of the force grows if every force is exerting itself in the same direction. The magnitude of the force diminishes when forces are applied to an object from various angles. Meters per second squared is the unit used to measure acceleration. The units must account for both variables since acceleration deals with both velocity and time. The object's current speed is represented by the magnitude of the velocity vector. The velocity vector is pointed in the same general direction as the object's motion. Multiply the constant acceleration rate by the time difference to determine the magnitude of the velocity at any given moment, and then add that value to the beginning velocity.
Learn more about Magnitude here:
brainly.com/question/28173919
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