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Nookie1986 [14]
2 years ago
7

15 PTS!!!!

Physics
2 answers:
faltersainse [42]2 years ago
7 0
B. group I think.
:))))))))
Anon25 [30]2 years ago
6 0
I thinks its period because they are on the last column to the right
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Which of the following shows kinetic energy being converted into potential energy?
Komok [63]
B) a rock being tossed high into the air
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You fill a car with gasoline. The car now has...
ValentinkaMS [17]

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  • Fuel or a provided source of energy for combustion
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2 years ago
What is the period of a wave that has a frequency of 300 hz?
Butoxors [25]

Answer:

T = 0.003 s

(Period is written as T)

Explanation:

Period = time it takes for one wave to pass (measured in seconds)

frequency = number of cycles that occur in 1 second

(measured in Hz / hertz / 1 second)

Period : T

frequency : f

So, if we know that the frequency of a wave is 300 Hz, we can find the period of the wave from the relation between frequency and period

T =  \frac{1}{f}    f = \frac{1}{T}

to find the period (T) of this wave, we need to plug in the frequency (f) of 300

T = \frac{1}{300}

T = 0.00333333333

So, the period of a wave that has a frequency of 300 Hz is 0.003 s

[the period/T of this wave is 0.003 s]

3 0
1 year ago
HELP PLZ ASAP!!!!!
zubka84 [21]

Answer:

C. Oxygen combines with carbon dioxide

Explanation:

B i o l o g y

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Hope it helps

5 0
2 years ago
A point charge q1 is held stationary at the origin. A second charge q2 is placed at point a, and the electric potential energy o
likoan [24]

Answer:

U_{b}=+7.3*10^{-8}J

Explanation:

Given data

Electric potential at point a is Ua=5.4×10⁻⁸J

q₂ moves to point b where a negative work done on it  W_{a-b}=-1.9*10^{-8}J

Required

Electric potential energy Ub

Solution

When a particle moves from a point where the potential is Ua to a point where it is Ub the change in potential energy is equal to work done where the force exerted on the charge is conservative and work done is given by:

W_{a-b}=U_{a}-U_{b}\\U_{b}=U_{a}-W_{a-b}

Now  substitute the given values

So

U_{b}=5.4*10^{-8}J-(-1.9*10^{-8}J)\\U_{b}=+7.3*10^{-8}J

3 0
3 years ago
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