All categories

3 years ago

15 PTS!!!!

Physics

2 answers:

faltersainse [42]3 years ago

7 0

B. group I think.
:))))))))

Anon25 [30]3 years ago

6 0

I thinks its period because they are on the last column to the right

You might be interested in

What is the kinetic energy of an object that has a mass of 12 kg and moves with a velocity of 10 m/s

WITCHER [35]

Answer:

600 J

Explanation:

The formula to find the kinetic energy of an object is $\frac{1}{2}mV^2$

m = mass in kg
V = velocity in m/s
KE is measured in Joules just as all other forms of energy.

Now, let's plug in the variables we're given and simplify.

$\frac{1}{2}(12)(10)^2$
$\frac{1}{2}(12)(100)$
$(6)(100)$
$(600)$

Thus, the answer is 600 Joules.

6 0

2 years ago

Read 2 more answers

Gamma rays have a higher frequency than visible light waves. What can you conclude from this?

NeTakaya

Answer:

i think it d

Explanation:

3 0

3 years ago

Read 2 more answers

Two ice skaters, Daniel (mass 70.0 kg) and Rebecca (mass 45.0 kg), are practicing. Daniel stops to tie his shoelace and, while a

wel

Answer:

a) $v=7.32m/s$

b) $\alpha =-35$ º

c) $ΔK=-1094.62J$

Explanation:

From the exercise we know that the collision between Daniel and Rebecca is elastic which means they do not stick together

So, If we analyze the collision we got

$p_{1x}=p_{2x}$

To simplify the problem, lets name D for Daniel and R for Rebecca

a) $p_{D1x}+p_{R1x}=p_{D2x}+p_{R2x}$

Since Daniel's initial velocity is 0

$m_{R}v_{Rx}=m_{D}v_{D2x}+m_{R}v_{R2x}$

$v_{D2x}=\frac{m_{R}*v_{R1x}-m_{R}*v_{R2x}}{m_{D}}$

$v_{D2x}=\frac{(45kg)(14m/s)-(45kg)(8cos(55.1)m/s)}{(70kg)}=6m/s$

Now, lets analyze the movement in the vertical direction

$p_{1y}=p_{2y}$

Since $p_{1y}=0$

$0=m_{D}v_{D2y}+m_{R}v_{R2y}$

$v_{D2y}=-\frac{m_{R}v_{2Ry}}{m_{D}}=-\frac{(45kg)(8sin(55.1)m/s)}{(70kg)}=-4.21m/s$

Now, we can find the magnitude of Daniel's velocity after de collision

$v_{D}=\sqrt{(6m/s)^2+(-4.21m/s)^2}=7.32m/s$

b) To know whats the direction of Daniel's velocity we need to solve the arctan of the angle

$\alpha =tan^{-1}(\frac{v_{y}}{v_{x}})=tan^{-1}(\frac{-4.21}{6})=-35$ º

c) The change in the total kinetic energy is:

ΔK= $K_{2}-K_{1}$

ΔK= $\frac{1}{2}[(45kg)(8m/s)^2+(70kg)(7.32m/s)^2-(45kg)(14m/s)^2]=-1094.62J$

That means that the kinetic energy decreases

5 0

2 years ago

Occasionally, people can survive falling large distances if the surface they land on is soft enough. During a traverse of Eiger'

uranmaximum [27]

Answer:

4611.58 ft/s²

Explanation:

t = Time taken

u = Initial velocity

v = Final velocity

s = Displacement

a = Acceleration due to gravity = 32.174 ft/s²

Equation of motion

$v^2-u^2=2as\\\Rightarrow v=\sqrt{2as+u^2}\\\Rightarrow v=\sqrt{2\times 32.174\times 516+0^2}\\\Rightarrow v=182.218\ ft/s$

$v^2-u^2=2as\\\Rightarrow a=\frac{v^2-u^2}{2s}\\\Rightarrow a=\frac{0^2-182.218^2}{2\times 3.6}\\\Rightarrow a=-4611.58\ ft/s^2$

Magnitude of acceleration while stopping is 4611.58 ft/s²

8 0

3 years ago

A horse performs 2600 joules of work pulling a wagon for 13 seconds. What is the horse's power? 33800 W 200 W 0.005 W 2600 WA ho

tensa zangetsu [6.8K]

Answer:

200 W

Explanation:

The power is given by the ratio between the amount of work done and the time taken to perform the work:

$P=\frac{W}{t}$

where in this problem we have

W = 2600 J is the work done

t = 13 s is the time taken to do the work

Substituting the numbers into the equation, we find

$P=\frac{2600 J}{13 s}=200 W$

6 0

3 years ago

Read 2 more answers