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3 years ago

All waves have what shape?

Physics

1 answer:

agasfer [191]3 years ago

6 0

Answer:

square? lol

Explanation:

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The parallel axis theorem relates Icm, the moment of inertia of an object about an axis passing through its center of mass, to I

erma4kov [3.2K]

Answer:

Part a)

$I_{end} = \frac{mL^2}{3}$

Part b)

$I_{edge} = \frac{2ma^2}{3}$

Explanation:

As we know that by parallel axis theorem we will have

$I_p = I_{cm} + Md^2$

Part a)

here we know that for a stick the moment of inertia for an axis passing through its COM is given as

$I = \frac{mL^2}{12}$

now if we need to find the inertia from its end then we will have

$I_{end} = I_{cm} + Md^2$

$I_{end} = \frac{mL^2}{12} + m(\frac{L}{2})^2$

$I_{end} = \frac{mL^2}{3}$

Part b)

here we know that for a cube the moment of inertia for an axis passing through its COM is given as

$I = \frac{ma^2}{6}$

now if we need to find the inertia about an axis passing through its edge

$I_{edge} = I_{cm} + Md^2$

$I_{edge} = \frac{ma^2}{6} + m(\frac{a}{\sqrt2})^2$

$I_{edge} = \frac{2ma^2}{3}$

7 0

3 years ago

Compare the energy consumption of two commonly used items in the household. Calculate the energy used by a 1.40 kW toaster oven,

Nikolay [14]

Explanation:

It is given that,

Power consumed by toaster oven, $P=1.4\ kW$

Time taken, t = 6 minutes = 0.1 hour

Energy used by toaster, $W_{toaster}=P\times t$

$W_{toaster}=1.4\ kW\times 0.1\ h=0.14\ kWh$

Similarly,

Power consumed by toaster oven, $P=11\ W$

Time taken, t = 9 minutes = 0.15 hour

Energy used by toaster, $W_{toaster}=P\times t$

$W_{toaster}=11\ W\times 0.15\ h=1.65\ Wh=0.0016\ kWh$

Hence, this is the required solution.

3 0

3 years ago

The graph shows two runners participating in a race.

Olin [163]

Answer:

'Daniela had a 5-meter head start, and Leonard caught up to her at 25 meters.'

Explanation:

hope that helps :)

6 0

2 years ago

Read 2 more answers

A 1000kg ar accelerates from rest to 25.0m/s in 4.20

bezimeni [28]

Answer:

74.4 kilowatts or 99.8 horsepower

Explanation:

The explanation is in the attachment.

7 0

3 years ago

The tension of a guitar string is increased by 40%. By what factor odes the fundamental frequency of vibration change? a. 1.13 b

bogdanovich [222]

Answer:

Explanation:

The fundamental frequency in string is expressed as;

F1 = 1/2L√T/m .... 1

L is the length of the string

T is the tension

m is the mass per unit length

If the tension is increased by 40%, the new tension will be;

T2 = T + 40%T

T2 = T + 0.4T

T2 = 1.4T

The new fundamental frequency will be;

F2 = 1/2L√1.4T/m ..... 2

Divide 1 by 2;

F2/F = (1/2L√1.4T/m)/1/2L√T/m)+

F2/F = √1.4T/m ÷ √T/m

F2/F = √1.4T/√m ×√m/√T

F2/F = √1.4T/√T

F2/F = 1.18√T/√T

F2/F = 1.18

F2 = 1.18F

Hence the fundamental frequency of vibration changes by a factor of 1.18

8 0

3 years ago