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lesya [120]
3 years ago
8

A combustion reaction often produces sodium chloride and water true or false

Chemistry
1 answer:
BartSMP [9]3 years ago
4 0

A combustion reaction often produces sodium chloride and water False.

<u>Explanation:</u>

The reaction that takes place between any substance and oxygen can be termed as a combustion. Any substance when they react with oxygen, it will produce a larger quantity of energy. This energy will take the form of heat and light.

Oxygen always act as one the most important reactant in a combustion reaction. A hydrocarbon that is contains hydrogen and carbon with it will be the next reactant of the combustion reaction.Any combustion reaction will produce the carbon dioxide and water as the result of that reaction.

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Which metalloid is often found in microchips, semiconductors, and sand?a. boron b. arsenic c. germanium d. silicon​
elena-14-01-66 [18.8K]

Answer:

silicon

Explanation:

Silicon. Silicon is often found in electronic devices, as well as the sand.

hope this helps UwU

5 0
3 years ago
Read 2 more answers
As you move down through the family of alkali metals, the first ionization energy ________ because
kompoz [17]
I’m pretty sure the answer is B
5 0
3 years ago
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4Na + O2 2Na2O
beks73 [17]
4
N
a
+
O
2
→
2
N
a
2
O
.
By the stoichiometry of this reaction if 5 mol natrium react, then 2.5 mol
N
a
2
O
should result.
Explanation:
The molecular mass of natrium oxide is
61.98

g
⋅
m
o
l
−
1
. If
5

m
o
l
natrium react, then
5
2

m
o
l
×
61.98

g
⋅
m
o
l
−
1

=

154.95

g
natrium oxide should result.
So what have I done here? First, I had a balanced chemical equation (this is the important step; is it balanced?). Then I used the stoichiometry to get the molar quantity of product, and converted this molar quantity to mass. If this is not clear, I am willing to have another go
5 0
3 years ago
A sample of gas is observed to effuse through a pourous barrier in 4.98 minutes. Under the same conditions, the same number of m
kogti [31]

Answer:

The molar mass of the unknown gas is \mathbf{ 51.865 \  g/mol}

Explanation:

Let assume that  the gas is  O2 gas

O2 gas is to effuse through a porous barrier in time t₁ = 4.98 minutes.

Under the same conditions;

the same number of moles of an unknown gas requires  time t₂  =  6.34 minutes to effuse through the same barrier.

From Graham's Law of Diffusion;

Graham's Law of Diffusion states that, at a constant temperature and pressure; the rate of diffusion of a gas is inversely proportional to the square root of its density.

i.e

R \  \alpha  \ \dfrac{1}{\sqrt{d}}

R = \dfrac{k}{d}  where K = constant

If we compare the rate o diffusion of two gases;

\dfrac{R_1}{R_2}= {\sqrt{\dfrac{d_2}{d_1}}

Since the density of a gas d is proportional to its relative molecular mass M. Then;

\dfrac{R_1}{R_2}= {\sqrt{\dfrac{M_2}{M_1}}

Rate is the reciprocal of time ; i.e

R = \dfrac{1}{t}

Thus; replacing the value of R into the above previous equation;we have:

\dfrac{R_1}{R_2}={\dfrac{t_2}{t_1}}

We can equally say:

{\dfrac{t_2}{t_1}}=  {\sqrt{\dfrac{M_2}{M_1}}

{\dfrac{6.34}{4.98}}=  {\sqrt{\dfrac{M_2}{32}}

M_2 = 32 \times ( \dfrac{6.34}{4.98})^2

M_2 = 32 \times ( 1.273092369)^2

M_2 = 32 \times 1.62076418

\mathbf{M_2 = 51.865 \  g/mol}

7 0
3 years ago
Why do electrons enter the 4s orbital before entering the 3d orbital?
Allisa [31]
Because that is the outer ring.
6 0
4 years ago
Read 2 more answers
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