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andreev551 [17]
3 years ago
13

A sample of pure copper has a mass of 5 grams calculate its volume

Chemistry
1 answer:
kolbaska11 [484]3 years ago
4 0
Moles of cu = mass/Ar
= 5/Ar
=ans

1 mole = 24dm3

Vol of cu = ans/1 × 24dm3
=ans

sorry i have no calculator with me now
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Pt 2. Chem Reactions 50 PTS
Dahasolnce [82]

The red colour is the limiting reactant.

Red-blue colour ball and two white balls attached together are reactants.

Red-blue colour ball and two white and one red colour ball attached to each other are products.

<h3>What is a limiting reagent?</h3>

The reactant that is entirely used up in a reaction is called a limiting reagent.

A reactant is a substance that is present at the start of a chemical reaction. The substance(s) to the right of the arrow are called products.

A product is a substance that is present at the end of a chemical reaction.

Hence,

The red colour is the limiting reactant.

Red-blue colour ball and two white balls attached together are reactants.

Red-blue colour ball and two white and one red colour ball attached to each other are products.

Learn more about limiting reagents here:

brainly.com/question/26905271

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2 years ago
Drag each tile to the correct box.
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Answer:

Mercury, Earth, Saturn, Jupiter, and the sun

Explanation:

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3 years ago
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Which phrase describes properties of a solid?
Licemer1 [7]

Answer: fixed shape and volume

Explanation:

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6 0
2 years ago
Define organic chemistry and inorganic chemistry.
MrRissso [65]
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For the reaction: 2 A (g) + B (s)= 2 C(s) + D (g)
jolli1 [7]

Answer:

The value of the equilibrium constant = 5.213

Explanation:

Here K_p (equilibrium constant) is referred to as the  partial pressure of product divided by the  partial pressure of reactant with each pressure term raised to power that is equal to its stoichiometric coefficient in balanced equation .

As such only gas appear in K_p  expression as solids takes a value of 1;

SO ; in the  given equation from the question:

2 A (g) + B (s) ----> 2 C(s) + D (g)

K_p = \dfrac{[D]}{[A]^2}

K_p = \dfrac{2.71}{0.721^2}

K_p = 5.213

The value of the equilibrium constant = 5.213

8 0
3 years ago
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