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3 years ago

Pls help me, ill mark brainliest and give 5 stars

Chemistry

2 answers:

algol133 years ago

7 0

Answer:

ayo sooooo roasie how did u get ur mindreading superpowers cuz u read my mind when i was ab answer

Explanation:

Maslowich3 years ago

5 0

Answer:

Decomposition!

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This graduated cylinder has numbers representing milliliters. A student says that the volume of the liquid inside is 21.8 millil

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The answer for this question depends on the type of meniscus in the cylinder. If it is an upright meniscus like in water, the reading should be taken at the bottom of the meniscus. However if it is an inverted meniscus like in mercury, the reading should be taken at the top of the meniscus.

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3 years ago

Which of the following elements will form covalent bonds?

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A geologist finds ripples preserved in ancient sedimentary rock that look just like ripples made by water in mud. He concludes t

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4 years ago

Read 2 more answers

For the chemical reaction:

Julli [10]

Answer:

Volume of ammonia produced = 398.7 dm³

Explanation:

Given data:

Volume of N₂ = 200 dm³

Pressure and temperature = standard

Volume of ammonia produced = ?

Solution:

Chemical equation:

N₂ + 3H₂ → 2NH₃

Number of moles of N₂:

PV = nRT

1 atm× 200 L = n× 0.0821 atm.L/mol.K × 273 K

n = 200 atm.L /22.41 atm.L/mol

n = 8.9 mol

Now we will compare the moles of ammonia and nitrogen.

N₂ : NH₃

1 : 2

8.9 : 2/1×8.9 = 17.8 mol

Volume of ammonia:

1 mole of any gas occupy 22.4 dm³ volume

17.8 mol ×22.4 dm³/1 mol = 398.7 dm³

4 0

3 years ago

How many milliliters o a suspension base must be mixed with 250 mL o a paroxetine (PAXIL) oral suspension, 10 mg/5 mL, to change

Maksim231197 [3]

Answer : The suspension base added will be, 250 mL

Explanation :

As we are given that the initial concentration of solution is, 10 mg/5mL or we can say that 2 mg/mL.

Volume of solution = 250 mL

First we have to determine the mass of PAXIL.

As, 1 mL of solution contain mass of PAXIL = 2 mg

So, 250 mL of solution contain mass of PAXIL = $250\times 2=500mg$

Now we have to determine the final solution required.

As we are given the final concentration of solution is, 0.1 % w/v that means 0.1 g in 100 mL of solution.

Concentration of solution = $\frac{0.1g}{100mL}=\frac{0.1\times 1000mg}{100mL}=\frac{100mg}{100mL}=\frac{1mg}{mL}$

Let the 'x' mL of the suspension base is added. So, the ratio of mass and volume will be:

$\frac{500mg}{(x+250)mL}=\frac{1mg}{1mL}$

$x=250mL$

Thus, the suspension base added will be, 250 mL

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3 years ago