True.
As the length of the conductor increases, so also the resistance to the flow of current increases along the conductor.
Answer: 20.4 miles
Explanation:
Here we need to use the equation:
Velocity = Distance/Time.
Initially we have that he can travel 30 miles in 2 hours, so the velocity is:
V = 30mi/2h = 15mph
Now, we reduce the velocity by 3 mph, so the new velocity is 15mph - 3 mph = 12mph.
Now we want to know the distance traveled in 1.7 hours with this velocity, this is.
Velocity*Time = Distance
12mi/h*1.7h = 20.4 miles
Given data in the problem :-
- Acceleration (a) = 4.0 m/s^2
- Initial velocity (u) = 0 m/s
- Final velocity (v) = 34 m/s
- Distance travelled by aircraft (S) = ?
From Newton's Laws of Motion we know that ,
v = u + at [t = Time taken by aircraft to cover the distance]
⇒ 34 = 0 + 4t
⇒ t = 34/4 s
∴ t = 8.5 s
From Newton's Laws of Motion we also know that ,
S = u.t + 1/2a.t^2
⇒ S = 0×8.5 + 1/2 × 4 × (8.5)^2 m
∴ S = 144.50 m
Thus the distance travelled by the aircraft while accelerating is 144.50 meter .
I think it’s cause no change i think
