Answer:
0.78m/s
Explanation:
Now the momentum ensued by the boy throwing the package Is
Mass of package × velocity of package =4.5×13=58.5m/s
This momentum initiated a momentum on the boy-boat system
Total mass of the boy-boat system is 24+53=75kg
Let the velocity ensued by the boat be v.
Hence from conservation of momentum
58.5 =75×v
v= 58.5/75= 0.78m/s
(a) the principle of aerodynamic convergence
(b) the centripetal force
(c) Conservation of angular momentum
(d) Conservation of kinetic energy
(e) None of these
Conservation of angular momentum
Answer: Option C.
<u>Explanation:</u>
The law of conservation of angular momentum expresses that when no outer torque follows up on an article, no difference in precise force will happen.
The law of conservation of angular momentum expresses that the angular energy of a body that is the result of its snapshot of latency about the hub of revolution and its rakish speed about a similar pivot, can't change except if an outside torque follows up on the framework.
Answer:
The hammer and the wall exert forces on each other that are equal in magnitude but in opposite directions.
Explanation:
currently doing corrections on the test!
:)
Answer:
Explanation:
Given:
- mass of car,
- distance of skidding after the application of brakes,
- coefficient of kinetic friction,
<u>So, the energy dissipated during the skidding of car:</u>
<em>Frictional force:</em>
where N = normal reaction by ground on the car
<em>Now from the work-energy equivalence:</em>
is the dissipated energy.
I believe this is it
The centripetal force is given by
F = mv^2 / r
When v' = v/2,
F' = mv'^2/r = m(v/2)^2/r = mv^2/4r = F/4.
So the centripetal force is divided by 4.
