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____ [38]
3 years ago
12

A steel block has a volume of 0.08 m³ and a density of 7,840 kg/m³. What is the force of gravity acting on the block (the weight

) in water?
Physics
2 answers:
Blababa [14]3 years ago
3 0
d=\frac{m}{V}\\
\\
0.08 = \frac{m}{7,840}\rightarrow m=0.08 * 7,840=627.2 \ kg

\vec{F_g}=m.\vec{g}=627.2 *9.8=6,146.56 \ N
Anni [7]3 years ago
3 0
Density = 7840 kg per m³
Volume = 0.08 m³
Mass = 0.08 of 7840 kg = 627.2 kg

Now I'm going to give you the correct answer to your question, and then,
after that, I'm also going to give you the answer you expect.

The correct answer is:  (Ryan2 the Expert in Answer #1 is correct) . . . . .

The force of gravity on a mass doesn't depend on what it's sunk in, surrounded by,
hanging from, or resting on.  As long as it's on or near the Earth's surface, the force
of gravity acting on it is the same, no matter what else is around.

Force of gravity (weight) = (mass) x (gravity) = 627.2 kg x 9.8 m/s² = 6146.56 newtons
=============================================

The apparent weight is less, because when it's immersed in a fluid, there's
a buoyant force acting on it, which cancels part of the force of gravity.

The buoyant force = weight of the displaced water.

Assume the density of water is 1 kg per liter = 1,000 kg per m³.

Then the weight of 0.08 m³ of water is (80 kg x 9.8 m/s²) = 784 newtons.

This is the upward buoyant force on the steel when it's in water,
and it makes the steel seem 784 newtons lighter in water.  So the
apparent weight of the steel in water is

6146.56 minus 784 = 5362.56 newtons.

That's why you can pick up your big brother in the swimming pool.
The force of gravity on him doesn't change, but the buoyant force
in the water balances part of the force of gravity, and makes him
seem to weigh less.

If he could blow himself up like a balloon, and displace enough water
to weigh just as much as he really does, then the buoyant force would
cancel his weight completely, and he would totally float !

That's how steel ships float in water.  They're shaped in a shape that can
displace a lot of water.  The whole secret is in the shape.
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The rocket is fired vertically and tracked by the radar station shown. When θ reaches 66°, other corresponding measurements give
Flauer [41]

Answer:

velocity = 1527.52 ft/s

Acceleration = 80.13 ft/s²

Explanation:

We are given;

Radius of rotation; r = 32,700 ft

Radial acceleration; a_r = r¨ = 85 ft/s²

Angular velocity; ω = θ˙˙ = 0.019 rad/s

Also, angle θ reaches 66°

So, velocity of the rocket for the given position will be;

v = rθ˙˙/cos θ

so, v = 32700 × 0.019/ cos 66

v = 1527.52 ft/s

Acceleration is given by the formula ;

a = a_r/sinθ

For the given position,

a_r = r¨ - r(θ˙˙)²

Thus,

a = (r¨ - r(θ˙˙)²)/sinθ

Plugging in the relevant values, we obtain;

a = (85 - 32700(0.019)²)/sin66

a = (85 - 11.8047)/0.9135

a = 80.13 ft/s²

4 0
3 years ago
Which of the following is true?
fenix001 [56]

Answer:

Its either A. Or C cause ive had a question like this before So Im sure But if not Then Im so sorry

8 0
3 years ago
On a straight, level, two-lane road, two cars moving in opposite directions approach and pass each other. Car A is in the eastbo
ludmilkaskok [199]

Answer:

a) 42 m/s, positive direction (to the east), b) 42 m/s, negative direction (to the west).

Explanation:

a) Let consider that Car A is moving at positive direction. Then, the relative velocity of Car A as seen by the driver of Car B is:

\vec v_{A/B} = \vec v_{A} - \vec v_{B}\\\vec v_{A/B} = 11 \frac{m}{s} \cdot i + 31 \frac{m}{s} \cdot i\\\vec v_{A/B} = 42 \frac{m}{s} \cdot i

42 m/s, positive direction (to the east).

b) The relative velocity of Car B as seen by the drive of Car A is:

\vec v_{B/A} = \vec v_{B} - \vec v_{A}\\\vec v_{B/A} = -31 \frac{m}{s} \cdot i - 11 \frac{m}{s} \cdot i\\\vec v_{B/A} = - 42 \frac{m}{s} \cdot i

42 m/s, negative direction (to the west).

5 0
3 years ago
Calculate the force exerted on the wall assuming that force is horizontal and using the data in the schematic representation of
Jlenok [28]

Answer:

1.93 x 10∧3 N

Explanation:

The picture attached shows the calculation

8 0
3 years ago
tourist travels 1500 miles using two planes. The second plane averages 50 miles per hour faster than the first plane. The touris
Genrish500 [490]

Answer

given,

tourist travels = 1500 miles

second plane averages 50 miles per hour faster than the first plane.

x = y + 50

The tourist uses the slower plane for the first 500 and the faster plane for the next 1000 miles.

total flying time = 6.5 hours

\dfrac{500}{y} + \dfrac{1000}{x} = 6.5

\dfrac{500}{y} + \dfrac{1000}{y + 50} = 6.5

\dfrac{500(50 + y)+ 1000 y}{y(y + 50)} = 6.5

25000 + 600 y = 6.5 y^2 + 325 y

6.5 y^2 - 275 y - 25000 = 0

on solving equation

y = 86.67 mile/hr

x = 86.67 + 50

x = 136.67 mile/hr

8 0
3 years ago
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