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3 years ago

12

A ball rolls down an incline with an acceleration of 10 cm/s^2. If it starts with an initial velocity of 0 cm/s and has a velocy

of 50 cm/s when it reaches the bottom of the ramp, how long is the ramp?

1 answer:

11Alexandr11 [23.1K]3 years ago

8 0

Given a = 10 cm/s²
u = 0 cm/s
v = 50 cm/s
we know that
v²=u²+2aS
2500=2×10×S
2500÷20 = S
S= 125 cm
The ramp is 125 cm

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Answer:Answer

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Answer:

u = 15m/s

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Answer:

Explanation:

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(a) Use lens maker formula

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(b)

R1 = + 18.7 cm

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$\frac{1}{f}=\left ( 1.52-1 \right )\left ( \frac{1}{18.7}}+\frac{1}{11.7} \right )$

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(a) $2.56\cdot 10^{-5} C$

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