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vfiekz [6]
3 years ago
7

Oscilloscope time base problem. You are asked to display a 1 kHzsine wave signal on the screen. Since the period T is related to

the frequency f by the formula T = 1 / f, the period of this waveis 1/(103/s)=1ms, so a reasonable setting for the"Time/div" dial is 1 ms/div. But suppose you select aninappropriate setting for the Time/div dial by mistake. What wouldyou see if you set the dial on 1 μ s/div?100 ms/div?A. Asine wave shifted to the left on 1 μ s/div and to the right on100 ms/divB. A(nearly) horizontal line on 1 μ s/div andmany (nearly) vertical lines of 100 ms/divC.Nothing on either (no trigger)D. Anormal sine wave in both casesE.None of these
Physics
1 answer:
Dmitrij [34]3 years ago
5 0

Answer:

B.

Explanation:

If we need to show on the screen a sine wave of 1 Khz, this means that the period (time to complete one cycle), will be 1/f = 1 ms.

So, in order to show some cycles on the screen at the same time, it is reasonable to choose a 1ms/div setting for "Time/div" dial.

If we by mistake choose a much much shorter setting (like 1 μs/div), what we will look at the screen will be very different, as we will be looking at 1/1000 of a cycle per div, so we wil see a nearly horizontal line.

If instead we choose 100 ms/div, this means that each division  will show 100 cycles of the sine wave, that they will look at if they were a lot of nearly vertical lines very closely spaced.

So, the statement B). is the one that is true.

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sergeinik [125]

The question is incomplete, the atoms in the third period referred to in the question are shown in the image attached.

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