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vagabundo [1.1K]
2 years ago
10

A 73.9 kg weight-watcher wishes to climb a

Physics
1 answer:
Tresset [83]2 years ago
7 0

The height to which the weight-watcher must climb to work off the equivalent 991 (food) Calories is 0.59 Km

<h3>How to determine the energy. </h3>

1 food calorie = 103 calories

Therefore,

991 food calories = 991 × 103

991 food calories = 102073 calories

Multiply by 4.2 to express in joule (J)

991 food calories = 102073 × 4.2

991 food calories = 428706.6 J

<h3>How to determine the height </h3>
  • Energy (E) = 428706.6 J
  • Mass (m) = 73.9 kg
  • Acceleration due to gravity (g) = 9.8 m/s²
  • Height (h) =?

E = mgh

Divide both side by mg

h = E / mg

h = 428706.6 / (73.9 × 9.8)

h = 591.95 m

Divide by 1000 to express in km

h = 591.95 / 1000

h = 0.59 Km

Learn more about energy:

brainly.com/question/10703928

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I think it's c

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Help me ultra sound vs infrasound
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A cat is sleeping on the dashboard of a moving car. Imagine that the cat does not wake up and is not touched by anything. Use Ne
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What do we call an object displaced by an unbalanced Force,
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And we also know that,
Due to acceleration, An object displaces.

But I'll use Newton's 1st law to prove it,
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As per the his law,
The cat will remain on the dashboard of that moving car until it is compelled by Air Force (external Force).

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7 0
3 years ago
If a truck loses 5610 J of energy as it slows down due to an external force of 425 N, what distance will it have moved after the
lara31 [8.8K]

Answer:

13.2m

Explanation:

Step one:

given data

Energy= 5610J

Force F= 425N

Required

The distance traveled

Step two:

We know that work done is given as

WD= force* distance

so

5610=425*d

divide both sides by 425

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3 0
3 years ago
You are on your balcony and notice some bad squirrels digging in your garden directly below. You start tossing your pistachios a
Rashid [163]

Answer:

0.43 s

Explanation:

We have the following parameters:

Initial velocity, u = 7.4 m/s

Acceleration of gravity, g = 9.8 m/s^2

Distance, s = 43 in + 10 ft = 1.092 m + 3.048 m = 4.14 m

Time, t = ?

Using the equation of motion s=ut +\frac{1}{2}gt^2, we have

4.14 = 7.4t + 0.5\times9.8t^2

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Using the quadratic formula \dfrac{-b\pm\sqrt{b^2-4ac}}{2a} where a = 4.9, b = 7.4 and c = - 4.14, and solving for the positive value of t only, we have

t = 0.43 s

3 0
3 years ago
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