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2 years ago

A 73.9 kg weight-watcher wishes to climb a

Physics

1 answer:

Tresset [83]2 years ago

7 0

The height to which the weight-watcher must climb to work off the equivalent 991 (food) Calories is 0.59 Km

<h3>How to determine the energy. </h3>

1 food calorie = 103 calories

Therefore,

991 food calories = 991 × 103

991 food calories = 102073 calories

Multiply by 4.2 to express in joule (J)

991 food calories = 102073 × 4.2

991 food calories = 428706.6 J

<h3>How to determine the height </h3>

Energy (E) = 428706.6 J
Mass (m) = 73.9 kg
Acceleration due to gravity (g) = 9.8 m/s²

Height (h) =?

E = mgh

Divide both side by mg

h = E / mg

h = 428706.6 / (73.9 × 9.8)

h = 591.95 m

Divide by 1000 to express in km

h = 591.95 / 1000

h = 0.59 Km

Learn more about energy:

brainly.com/question/10703928

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Imagine holding two identical bricks under water. Brick A is just beneath the surface of the water, while brick B is at a greate

FromTheMoon [43]

Answer:

I think it's c

Explanation:

The brick's mass, helps to hold it under the water but brick A is being held up. If you dropped the brick, it would sink to the bottom. You need a stronger force to hold it up.

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3 years ago

Help me ultra sound vs infrasound

hodyreva [135]

Answer:

ultrasound: high pitch, above the human range of hearing, reflects back

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Explanation:

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3 years ago

A cat is sleeping on the dashboard of a moving car. Imagine that the cat does not wake up and is not touched by anything. Use Ne

Minchanka [31]

What do we call an object displaced by an unbalanced Force,
Accelerated object,

And we also know that,
Due to acceleration, An object displaces.

But I'll use Newton's 1st law to prove it,
Which is, An object will remain in rest or in uniform motion until it is compelled by an external Force.

As per the his law,
The cat will remain on the dashboard of that moving car until it is compelled by Air Force (external Force).

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3 years ago

If a truck loses 5610 J of energy as it slows down due to an external force of 425 N, what distance will it have moved after the

lara31 [8.8K]

Answer:

13.2m

Explanation:

Step one:

given data

Energy= 5610J

Force F= 425N

Required

The distance traveled

Step two:

We know that work done is given as

WD= force* distance

5610=425*d

divide both sides by 425

d= 5610/425

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3 0

3 years ago

You are on your balcony and notice some bad squirrels digging in your garden directly below. You start tossing your pistachios a

Rashid [163]

Answer:

0.43 s

Explanation:

We have the following parameters:

Initial velocity, u = 7.4 m/s

Acceleration of gravity, g = 9.8 $m/s^2$

Distance, s = 43 in + 10 ft = 1.092 m + 3.048 m = 4.14 m

Time, t = ?

Using the equation of motion $s=ut +\frac{1}{2}gt^2$ , we have

$4.14 = 7.4t + 0.5\times9.8t^2$

$4.9t^2 + 7.4t - 4.14 =0$

Using the quadratic formula $\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}$ where a = 4.9, b = 7.4 and c = - 4.14, and solving for the positive value of t only, we have

$t = 0.43$ s

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3 years ago