Answer:
The surface charge density of the sheet is 1547.516 C/m²
Explanation:
Given;
force experienced by the proton, F = 14.0 μN
Electric field near an infinite sheet with surface charge density (σ) is given as;
E = σ/2ε₀
The force of attraction the proton experienced towards the sheet;
F = Eq
F = q(σ/2ε₀)
where;
q is the charge of the proton
σ is the surface charge density of the sheet
ε₀ is the permittivity of free space
Therefore, the surface charge density of the sheet is 1547.516 C/m²
Answer:
75.71 m/s
Explanation:
From equation of motion, acceleration is given by
where v is the final velocity, u is the initial velocity and t is time taken.
Making v the subject of the above formula
v=at+u
Substituting 6.7 s for time, t and 11.3 for a and taking u as zero since it starts from rest
v=11.3*6.7=75.71 m/s
Answer:
Its initial position was 471 m.
Explanation:
We have,
Final position of the object is 327 m
Displacement of the object is -144 m
It is required to find its initial position. The difference of final and initial position is equal to the displacement of the object. So,
So, its initial position was 471 m.