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3 years ago

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Para levantar del suelo una caja metálica de 50 Kg se emplea maquinaria que utiliza un cable inextensible e imprime una acelerac

ión de 0,8 m/seg2. ¿Qué tensión soporta el cable y qué tiempo le tomará a la máquina levantar la caja a una altura de 10 metros? Lo necesito urgente

1 answer:

dimulka [17.4K]3 years ago

4 0

Answer:

T = 530 N , t = 12.65 s

Explanation:

This is an exercise on Newton's second law,

T - W = m a

where T is the tension of the cable, W the weight and the steel of the box

T = W + ma

the weight of a body is

W = m g

Let's replace

T = m g + ma

T = m (g + a)

let's calculate

T = 50 (9.8 + 0.8)

T = 530 N

To calculate the time we use

y = v₀t + ½ a t²

since the box starts from rest on the sole its initial velocity is zero

y = ½ a t2

t = √ 2y / a

let's calculate

t = √ (2 10 / 0.8)

t = 12.65 s

TRASLATE

Este es un ejercicio de la segunda ley de Newton,

T – W = m a

donde T es la tension del cable, W el peso y a la aceracion de la caja

T = W + ma

el pesode un cuerpo es

W = m g

Substituyamos

T = m g + ma

T = m ( g +a)

calculemos

T = 50 ( 9,8 + 0,8)

T = 530 N

Para calcular el tiempo usamos

y = v₀t + ½ a t²

como la caja parte del reposo en el suela su velocidad inicial es cero

y= ½ a t²

t= √ 2y/a

calculemos

t = √ (2 10/0,8)

t = 12,65 s

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