The atom that is the most electronegative is fluorine (F).
<h3>
What is electronegative?</h3>
Electronegativity, is the tendency for an atom of a given chemical element to attract shared electrons when forming a chemical bond.
Electronegativity increases across the groups from left to right of the periodic table and decreases down the group.
Examples of electronegative elements arranged in decreasing order;
- fluorine,
- oxygen,
- nitrogen,
- chlorine,
- bromine,
- iodine,
- sulfur,
- carbon, and
- hydrogen.
Thus, the atom that is the most electronegative is fluorine (F).
Learn more about electronegativity here: brainly.com/question/24977425
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Answer:
35.6 N
Explanation:
We can consider only the forces acting along the horizontal direction to solve the problem.
There are two forces acting along the horizontal direction:
- The horizontal component of the pushing force, which is given by
![F_x = F cos \theta](https://tex.z-dn.net/?f=F_x%20%3D%20F%20cos%20%5Ctheta)
with ![\theta=41.9^{\circ}](https://tex.z-dn.net/?f=%5Ctheta%3D41.9%5E%7B%5Ccirc%7D)
- The frictional force, whose magnitude is
![F_f = \mu mg](https://tex.z-dn.net/?f=F_f%20%3D%20%5Cmu%20mg)
where
, m=8.2 kg and g=9.8 m/s^2.
The two forces have opposite directions (because the frictional force is always opposite to the motion), and their resultant must be zero, because the suitcase is moving with constant velocity (which means acceleration equals zero, so according to Newton's second law: F=ma, the net force is zero). So we can write:
![F_x - F_f=0\\F_x = F_f\\F cos \theta = \mu mg\\F=\frac{\mu mg}{cos \theta}=\frac{(0.33)(8.2 kg)(9.8 m/s^2)}{cos(41.9^{\circ})}=35.6 N](https://tex.z-dn.net/?f=F_x%20-%20F_f%3D0%5C%5CF_x%20%3D%20F_f%5C%5CF%20cos%20%5Ctheta%20%3D%20%5Cmu%20mg%5C%5CF%3D%5Cfrac%7B%5Cmu%20mg%7D%7Bcos%20%5Ctheta%7D%3D%5Cfrac%7B%280.33%29%288.2%20kg%29%289.8%20m%2Fs%5E2%29%7D%7Bcos%2841.9%5E%7B%5Ccirc%7D%29%7D%3D35.6%20N)
Answer:
Exercise 1;
The centripetal acceleration is approximately 94.52 m/s²
Explanation:
1) The given parameters are;
The diameter of the circle = 8 cm = 0.08 m
The radius of the circle = Diameter/2 = 0.08/2 = 0.04 m
The speed of motion = 7 km/h = 1.944444 m/s
The centripetal acceleration = v²/r = 1.944444²/0.04 ≈ 94.52 m/s²
The centripetal acceleration ≈ 94.52 m/s²