Complete question is;
In searching the bottom of a pool at night, a watchman shines a narrow beam of light from his flashlight 125 cm above the water level to a point 185 cm from his foot at the edge of the pool. Where does the spot of light hit the bottom of the pool, relative to the edge, if the pool is 215 cm deep
Answer:
356.2 cm
Explanation:
First of all, let's find the angle of incidence from the distances
;
tan θ1 = l1/h1
tan θ1 = 185/125
tan θ1 = 1.48
θ1 = tan^(-1) 1.48
θ1 = 55.95°
For the refraction from air into water, we have
n_air × sin θ1 = n_water × sin θ2,
sin θ2 = (n_air × sin θ1)/n_water
Where,
n_water is refractive index of water = 1.33
n_air is refractive index of air = 1
Thus;
sin θ2 = (1 × sin 55.95)/1.33
sin θ2 = 0.62297
θ2 = sin^(-1) 0.62297
θ2 = 38.53°
So, the horizontal distance from the edge of the pool from
l is;
l = l1 + l2 = l1 + h2 tan θ2
where;
l1 = 185cm
h2 = 215 cm
So,
l = 185 + 215(tan 38.53)
l = 185 + 171.2045
l = 356.2045 cm ≈ 356.2 cm
Answer:
Newton's Second Law is applied because of the acceleration caused by natural forces as the egg is plummeting to the earth. And the amount of acceleration the egg has will be largely affected by the amount of force Mr. Baker uses to hurl the egg to the ground.
Explanation:
hope that helps
F = 2820.1 N
Explanation:
Let the (+)x-axis be up along the slope. The component of the weight of the crate along the slope is -mgsin15° (pointing down the slope). The force that keeps the crate from sliding is F. Therefore, we can write Newton's 2nd law along the x-axis as
Fnet = ma = 0 (a = 0 no sliding)
= F - mgsin15°
= 0
or
F = mgsin15°
= (120 kg)(9.8 m/s^2)sin15°
= 2820.1 N
Gravitational potential energy is energy an object possesses because of its position in a gravitational field. The equation for gravitational potential energy is GPE = mgh.
GPE = 1200(1.6)(350) = 672000 J
Hope this answers the question. Have a nice day.
In exothermic/exergonic reactions, reactants have greater energy(Gibbs-Free Energy) than the products. This energy determines how much mechanical work a system can do
