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Harman [31]
4 years ago
11

Are limiting reagents present in all reactions? Explain

Chemistry
1 answer:
nexus9112 [7]4 years ago
6 0

Limiting reagents doesn't present in all reactions.

No. not at all

<u>Explanation:</u>

In any chemical reaction, the reactant which is used first is called as limiting reagent. From a mathematical point of view, there always won't be any limiting reagent. But in the molecular perspective, in a reaction, one of the reactant must used up since we can't count the atoms accurately.

Consequently even if there is an ideal stoichiometric ratio by means of moles mathematically, there may not exist a perfect stoichiometric ratio in terms of molecules probably in molecular view point.

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What can you conclude from the figure shown?
arlik [135]

Answer:

A. Hund's rule has been violated

Explanation:

There must be one electron with the same spin in each orbital of the same energy before you can put two in the same orbital. In the photo, the 2s sublevel is completely filled before the 1s sublevel (if anything the 1s should have an up spin and down spin, with the 2s having one up spin).

6 0
3 years ago
TRUE OR FALSE : Cell specialization is when a cell has a particular function or job. <br> help ?
liubo4ka [24]

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True

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3 years ago
What effect does observing a substance's physical properties have on the substance?
dybincka [34]
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5 0
3 years ago
A buffering solution consists of both strong acids and bases. <br> a. True<br> b. False
artcher [175]
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4 0
4 years ago
Writing a pressure equilibrium constant expression Ammonia and oxygen react to form nitrogen monoxide and water, like this: 4 NH
Sliva [168]

<u>Answer:</u> The equilibrium constant expression for the given equation is written below.

<u>Explanation:</u>

Equilibrium constant in terms of partial pressure is defined as the ratio of partial pressures of products to the partial pressures of reactants each raised to the power their stoichiometric ratios. It is expressed as K_{p}

For the general chemical equation:

aA+bB\rightleftharpoons cC+dD

The expression of K_p follows:

K_p=\frac{p_C^c\times p_D^d}{p_A^a\times p_B^b}

For the given chemical equation:

4NH_3(g)+5O_2(g)\rightleftharpoons 4NO(g)+6H_2O(g)

The expression of K_p for above equation follows:

K_p=\frac{(p_{H_2O}^5)\times (p_{NO}^4)}{(p_{NH_3}^4)\times (p_{O_2}^5)}

Hence, the equilibrium constant expression for the given equation is written above.

5 0
3 years ago
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