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MariettaO [177]
3 years ago
15

Writing a pressure equilibrium constant expression Ammonia and oxygen react to form nitrogen monoxide and water, like this: 4 NH

3(g)+5 O2(g)-4 NO(g)+6 H2O(g) Write the pressure equilibrium constant expression for this reaction.
Chemistry
1 answer:
Sliva [168]3 years ago
5 0

<u>Answer:</u> The equilibrium constant expression for the given equation is written below.

<u>Explanation:</u>

Equilibrium constant in terms of partial pressure is defined as the ratio of partial pressures of products to the partial pressures of reactants each raised to the power their stoichiometric ratios. It is expressed as K_{p}

For the general chemical equation:

aA+bB\rightleftharpoons cC+dD

The expression of K_p follows:

K_p=\frac{p_C^c\times p_D^d}{p_A^a\times p_B^b}

For the given chemical equation:

4NH_3(g)+5O_2(g)\rightleftharpoons 4NO(g)+6H_2O(g)

The expression of K_p for above equation follows:

K_p=\frac{(p_{H_2O}^5)\times (p_{NO}^4)}{(p_{NH_3}^4)\times (p_{O_2}^5)}

Hence, the equilibrium constant expression for the given equation is written above.

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A chemist prepares a solution of barium chloride by measuring out of barium chloride into a volumetric flask and filling the fla
mezya [45]

The given question is incomplete. The complete question is:

A chemist prepares a solution of barium chloride by measuring out 110 g of barium chloride into a 440 ml volumetric flask and filling the flask to the mark with water. Calculate the concentration in mole per liter of the chemist's barium chloride solution. Round your answer to 3 significant digits.

Answer: Concentration of the chemist's barium chloride solution is 1.20 mol/L

Explanation:

Molarity of a solution is defined as the number of moles of solute dissolved per liter of the solution.

Molarity=\frac{n\times }{V_s}

where,

n = moles of solute

V_s = volume of solution in L

moles of BaCl_2(solute) = \frac{\text {given mass}}{\text {Molar Mass}}=\frac{110g}{208g/mol}=0.529mol

Now put all the given values in the formula of molality, we get

Molality=\frac{0.529\times 1000}{440ml}=1.20mole/L

Therefore, the molarity of solution is 1.20 mol/L

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What are the observed effects of sleep deprivation on leptin and ghrelin?
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6 0
4 years ago
Hydroxylapatite, Ca10(PO4)6(OH)2, has a solubility constant of Ksp = 2.34 x 10^-59. Solid hydroxylapatite is dissolved in water
nadezda [96]

Answer:

The concentration of [Ca²⁺] is 8.47 x 10⁻³ M

Explanation:

We consider the solubility of hydroxyapatite,

Ca₁₀(PO₄)₆(OH)₂ ⇔ 10Ca²⁺ + 6PO₄³⁻ + 2 OH⁻

Assumed that there is <em>a</em> mol of hydoxyapatite disolved in water, yielding <em>10a</em> mol Ca²⁺ of  and <em>6a</em> mol of PO₄³⁻

We also have Ksp equation,

Ksp = [Ca²⁺]¹⁰ x [PO₄³⁻]⁶ x [OH⁻]² = 2.34 x 10⁻⁵⁹

     ⇔  10a¹⁰ x 6a⁶ x (5.30 x 10⁻⁶)² = 2.24 x 10⁻⁵⁹

     ⇔  60a¹⁶                                    = 2.24 x 10⁻⁵⁹ / 5.30 x 10⁻¹²

     ⇔  a¹⁶                                         = 0.007 x 10⁻⁴⁷ = 7 x 10⁻⁵⁰

     ⇔  a                                           = \sqrt[16]{7 . 10^{-50} } =  8.47 x 10⁻⁴

Hence,

[Ca²⁺] = 10<em>a</em> = 8.47 x 10⁻³ M

3 0
4 years ago
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