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Advocard [28]
3 years ago
6

TRUE OR FALSE : Cell specialization is when a cell has a particular function or job. help ?

Chemistry
1 answer:
liubo4ka [24]3 years ago
8 0

Answer:

True

Explanation:

Cell specialization is the process by which generic cells change into cells meant to do certain tasks within the body

hope this helps :)

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Homeostasis subheading<br> The maintenance of stable internal conditions is called
melamori03 [73]

Answer:

<h3>homeostasis</h3>

•the maintenance of a stable internal environment

<u><em>Hope </em><em>this</em><em> helps</em><em> </em><em>:</em><em>)</em></u>

6 0
3 years ago
Please help this is a test you in5 minutes I really need help I’ll give 10 points
kondaur [170]

Answer:

net force is 0

Explanation:

logccccccccccccccccc

3 0
3 years ago
Read 2 more answers
There are several aromatic compounds with the formula c8h9cl. Draw those that have a monosubstituted ring.
anygoal [31]

Answer:

As shown in the attachment.

Explanation:

In this case, there are two isomers possible. Isomers are compounds that have the same molecular formular but different structural formular.

Considering the hydrocarbon C8H10, which has 8C expected saturated hydrocarbon. however when there is an excess of 8H, we have C8H18 which is the formular of octane, a member of the alkane family and from monosubstitution reaction which involves reaction with halogens (particularly Chlorine), the reaction will be a repeated substitution reaction where chlorine will be replaced with each of the hydrogen.

8 0
4 years ago
Which is the correct equation for the reaction of magnesium with hydrochloric acid to produce hydrogen and magnesium chloride?
zimovet [89]
Answer is: a. Mg + 2HCl → H₂ + MgCl₂.
Reduction hald reaction: 2H⁺ + 2e⁻→ H₂.<span>
Oxidation half reaction: Mg</span>⁰ → Mg²⁺ + 2e⁻.
In this chemical reaction, magnesium lost two electrons (oxidation, change oxidation number from 0 to +2) and hydrogen gain that two electrons (reduction, change oxidation number from +1 to 0).
4 0
3 years ago
An atom has a diameter of 2.50 Å and the nucleus of that atom has a diameter of 9.00×10−5 Å . Determine the fraction of the volu
chubhunter [2.5K]

Answer:

The fraction of the volume of the atom that is taken up by the nucleus is 4.6656\times 10^{-14}.

The density of a proton is 6.278\times 10^{14} g/cm^3.

Explanation:

Diameter of the atom ,d = 2.50 Å

Radius of the atom ,r = 0.5 d=0.5 × 2.50 Å = 1.25Å

Volume of the sphere= \frac{4}{3}\pi r^3

Volume of atom = V

V=\frac{4}{3}\pi r^3..[1]

Diameter of the nucleus ,d' = 9.00\times 10^{-5}\AA

Radius of the nucleus ,r' = 0.5 d'=0.5\times 9.00\times 10^{-5}\AA=4.5\times 10^{-5}\AA

Volume of nucleus = V'

V=\frac{4}{3}\pi r'^3..[2]

Dividing [2] by [1]

\frac{V'}{V}=\frac{\frac{4}{3}\pi r'^3}{\frac{4}{3}\pi r^3}

=\frac{r'^3}{r^3}=\frac{(4.5\times 10^{-5}\AA)^3}{(1.25 \AA)^3}

\frac{V'}{V}=4.6656\times 10^{-14}

The fraction of the volume of the atom that is taken up by the nucleus is 4.6656\times 10^{-14}.

Diameter of the proton ,d = 1.72\times 10^{-15} m = 1.72\times 10^{-13} cm

1 m = 100 cm

Radius of the proton,r = 0.5 d=0.5\times 1.72\times 10^{-13} cm=8.6\times 10^{-14} cm

Volume of the sphere= \frac{4}{3}\pi r^3

Volume of atom = V

V=\frac{4}{3}\times 3.14\times (8.6\times 10^{-14} cm)^3=2.664\times 10^{-39}cm^3

Mass of proton, m = 1.0073 amu = 1.0073\times 1.66054\times 10^{-24} g

1 amu = 1.66054\times 10^{-24} g

Density of the proton : d

d=\frac{m}{V}=\frac{1.0073\times 1.66054\times 10^{-24} g}{2.664\times 10^{-39}cm^3}=6.278\times 10^{14} g/cm^3

The density of a proton is 6.278\times 10^{14} g/cm^3.

5 0
3 years ago
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