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iren [92.7K]
3 years ago
12

"how many particles would one formula unit of alcl3 produce when dissolved in solution?"

Chemistry
2 answers:
mote1985 [20]3 years ago
7 0
I think you mean “atoms”
And it’s 4 atoms
True [87]3 years ago
3 0

Answer: 4


Justification:


1) The dissolution of a formula unit of AlCl₃ is given by the chemical equation:


AlCl₃ (s) → Al₃⁺ + 3 Cl⁻


So, 1 unit of AlCl₃ yields 1 partilce of Al₃⁺ and 3 particles of Cl⁻.


2) You get that through a mass balance and the oxidation states (balance of charge).


i) Mass balance: the same number of atoms of each species must appear on the reactant and the product sides.


ii) The oxidation state of Al is 3+ and the oxidation state of Cl is 1-, so the total net charge is 3+ + 3(1-) = 3 - 3 = 0.

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Answer:

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Explanation:

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<em>PV = nRT.</em>

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V is the volume of the container.

n is the no. of moles of the gas.

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T is the temperature of the gas (K).

<em>1) What is the new pressure of 150 mL of a gas that is compressed to 50 mL when the original pressure was 2.0 atm and the temperature is held constant?</em>

  • At constant T and at two different (P, and V):

<em>P₁V₁ = P₂V₂.</em>

P₁ = 2.0 atm, V₁ = 150.0 mL.

P₂ = ??? atm, V₂ = 50.0 mL.

<em>∴ P₂ = P₁V₁/V₂</em> = (2.0 atm)(150.0 mL)/(50.0 mL) = <em>6.0 atm.</em>

<em>2. A sample of a gas in a rigid container at 30.0°C and 2.00 atm has its temperature increased to 40.0°C. What will be the new pressure?</em>

<em></em>

  • Since the container is rigid, so it has constant V.
  • At constant V and at two different (P, and T):

<em>P₁/T₁ = P₂/T₂.</em>

P₁ = 2.0 atm, T₁ = 30.0°C + 273 = 303 K.

P₂ = ??? atm, T₂ = 40.0°C + 273 = 313 K.

<em>∴ P₂ = P₁T₂/T₁ </em>= (2.0 atm)(313.0 K)/(303.0 K) =<em> 2.066 atm.</em>

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