I don’t know the first one but the second one is light and the third one is a satellite
W = 1/2k*x^2.
k = spring constant = 2500 n/m.
x = distance = 4 cm = 0.04m (convert to same units).
W = 1/2(2500)(0.04)^2 = 2J.
Answer:
The slopes shows that the direction of the field is from -2 to +2, with three point charges, q₁, q₂ and q₃ at -2, 0 and +2 respectively.
Explanation:
Given;
The slope, dy/dx = 2x(y-6) - 4
2x(y-6) - 4 = 2xy - 12x - 4, divide through by 'x'
dy/dx = 2y -12 - 4/x
The slopes of the linear elements on the lines, x =0, y = 5, y = 6, y = 7.
At x = 0, and y = 5
dy/dx = 2y -12 - 4/x
dy/dx = 2(5) - 12 = -2
At x = 0, and y = 6
dy/dx = 2y -12 - 4/x
dy/dx = 2(6) - 12 = 0
At x = 0, and y = 7
= 2y -12 - 4/x
dy/dx = 2(7) - 12 = 2
Therefore, the slopes shows that the direction of the field is from -2 to +2, with three point charges, q₁, q₂ and q₃ at -2, 0 and +2 respectively.
Answer:
Explanation:
Given
Inclination 
Distance of landing point 
Considering athlete to be an Projectile
range of projectile is given by
where u=launch velocity
(b)If u is increased by 8% then
new velocity is 
<span>We convert the Fahrenheit temperature to Celsius. C = F 32 F 5 C = 15 F 32 F 5 C = 26 C . The antifreeze only protects to 9 F 9 F 22 C and thus it will not offer protection to temperatures as low as 15 F = 26.1 C . 2A (E) The mass is the difference between the mass of the full and empty flask. density = 291.4 g 108.6 g = 1.46 g/mL 125 mL 2B (E) First determine the volume required. V = (1.000 × 103 g) (8.96 g cm-3) = 111.6 cm3. Next determine the radius using the relationship between volume of a sphere and radius. 4 4 111.6 3 r= 3 = 2.987 cm V = r3 = 111.6 cm3 = (3.1416)r3 3 3 4(3.1416) 3A (E) The volume of the stone is the difference between the level in the graduated cylinder with the stone present and with it absent. density = mass 28.4 g rock = = 2.76 g/mL = 2.76 g/cm3 volume 44.1 mL rock &water 33.8 mL water 3B (E) </span>
