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ArbitrLikvidat [17]
3 years ago
11

A flat (unbanked) curve on a highway has a radius of 220.0 m. A car rounds the curve at a speed of 25.0 m/s.

Physics
1 answer:
Salsk061 [2.6K]3 years ago
7 0

Answer:

Explanation:

the coefficient of static friction between the tires and pavement is only one-third of what you found in part (a). What should be the maximum speed of the car so ...

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When a person speaks, a sound intensity is generated that is 600 times greater than when the person whispers. What is the differ
Charra [1.4K]

Answer:

Originally :  Level = log I / I0

Currently: Level = 10 log I / I0

Level = 10 log 600 = 10 * 2.78 = 27.8

Note the term 1 bel = 10 decibels

5 0
2 years ago
(a) At what height above Earth’s surface is the energy required to lift a satellite to that height equal to the kinetic energy r
Nikitich [7]

Answer:

Explanation:

Gravitational Potential Energy at earth surface U_1=\frac{GM_em}{R_e}

Gravitational Potential Energy at height h is U_2=\frac{GM_em}{R_e+h}

Energy required to lift the satellite E_1=U_1-U_2

E_1=\frac{GM_em}{R_e}-\frac{GM_em}{R_e+h}

Now Energy required to orbit around the earth

E_2=\frac{1}{2}mv_{orbit}^2=\frac{GM_2m}{2(R_e+h)}

\Delta E=E_1-E_2

\Delta E=\frac{GM_em}{R_e}-\frac{GM_em}{R_e+h}-\frac{GM_2m}{2(R_e+h)}

E_1=E_2  (given)

\frac{GM_em}{R_e}-\frac{GM_em}{R_e+h}-\frac{GM_2m}{2(R_e+h)}=0

\frac{1}{R_e}-\frac{3}{2(R_e+h)}=0

h=\frac{R_e}{2}

h=3.19\times 10^6\ m

(b)For greater height E_1  is greater than E_2

thus energy to lift the satellite is more than orbiting around earth

4 0
3 years ago
How much work would it take to push two protons very slowly from a separation of 2.00×10−10m (a typical atomic distance) to 3.00
laiz [17]

Answer:

Work= -7.68×10⁻¹⁴J

Explanation:

Given data

q₁=q₂=1.6×10⁻¹⁹C

r₁=2.00×10⁻¹⁰m

r₂=3.00×10⁻¹⁵m

To find

Work

Solution

The work done on the charge is equal to difference in potential energy

W=ΔU

Work=U_{1}-U_{2}\\ Work=-kq_{1}q_{2}[\frac{1}{r_{2}}-\frac{1}{r_{1}} ]\\Work=(-9*10^{9})*(1.6*10^{-19} )^{2}[\frac{1}{3.0*10^{-15} }-\frac{1}{2*10^{-10} } ]\\  Work=-7.68*10^{-14}J

4 0
3 years ago
The work done by the brakes during braking is equal to
kow [346]

Answer:

The amount of pressure delivered to them

Explanation:

6 0
2 years ago
Predict what happens when glucose levels are high in the humms body
Goryan [66]

Glucose is blood sugar (hyperglycemia) comes from diabeties often, but can occur with other reasons, when glucose is to high someoenes sugar raises. Often this can lead to a diabetic coma, fatigue, vomiting, hospitalization, and even death if serious enough, from to high sugar. Many things can happen after this, and a lot are serious.

on the flip side (hypoglycemia) if sugar gets to low, confusion, fainting, vomiting, and nausea occur, as well as comas, and death if serious enought.

5 0
3 years ago
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