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Leokris [45]
2 years ago
15

What is measurement ?​

Physics
2 answers:
mojhsa [17]2 years ago
7 0

Answer:

Measurement is the assignment of a number to a characteristic of an object or event, which can be compared with other objects or event

Akimi4 [234]2 years ago
6 0

Answer:

Measurement is the assignment of a number to a characteristic of an object or event

Explanation:

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How many atoms of oxygen are there in one molecule of trinitrotoluene, if the chemical formula is C6H3(NO2)3?
kvasek [131]

。☆✼★ ━━━━━━━━━━━━━━  ☾  

2 x 3 = 6

Thus there are 6 atoms of oxygen in this molecule.

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6 0
3 years ago
Read 2 more answers
Una furgoneta circula por una carretera a 55km/h. Diez km atrás , un coche circula en el mismo sentido a 85km/h ¿ En cuanto tiem
statuscvo [17]

Answer:

t = 0.33h = 1200s

x = 18.33 km

Explanation:

If the origin of coordinates is at the second car, you can write the following equations for both cars:

car 1:

x=x_o+v_1t    (1)

xo = 10 km

v1 = 55km/h

car 2:

x'=v_2t    (2)

v2 = 85km/h

For a specific value of time t the positions of both cars are equal, that is, x=x'. You equal equations (1) and (2) and solve for t:

x=x'\\\\x_o+v_1t=v_2t\\\\(v_2-v_1)t=x_o\\\\t=\frac{x_o}{v_2-v_1}

t=\frac{10km}{85km/h-55km/h}=0.33h*\frac{3600s}{1h}=1200s

The position in which both cars coincides is:

x=(55km/h)(0.33h)=18.33km

6 0
3 years ago
What is the force exerted
Norma-Jean [14]

Answer:

I wish i saw the field shown to the right

Explanation:

3 0
3 years ago
Referring to the map of the temperature field in the room, where was the warmest field found?
klasskru [66]
Is there supposed to be an image if so there is none
8 0
3 years ago
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You drive a car 1600 ft to the east, then 2500 ft to the north. The trip took 2.5 minutes. What was the magnitude of your averag
elena-14-01-66 [18.8K]

Answer:

Velocity=6.03m/s

Explanation:

Given data

Time t=2.5 minutes=150 seconds

Distance A=1600 ft=487.68 m........east

Distance B=2500 ft=762m ........north

To find

Average velocity

Solution

First we need to find the resultant distance magnitude.To find that we apply Pythagorean theorem to find hypotenuse

So

A^{2}+B^{2}=C^{2}\\  C=\sqrt{A^{2}+B^{2}}\\ C=\sqrt{(487.68m)^{2}+(762m)^{2}}\\ C=904.7m

Velocity=\frac{Distance}{Time}\\Velocity=\frac{904.7m}{150s}\\Velocity=6.03m/s

7 0
3 years ago
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