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3 years ago

Which county in Florida is most in need of safe rooms and hurricane ties?

Physics

2 answers:

Murrr4er [49]3 years ago

8 0

Probably Pasco. Lol.

liq [111]3 years ago

7 0

Answer:

the answer is Miami-Dade

Explanation:

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I need help with two more Physics problems

sesenic [268]

Answer:

c. They hit at the same time

b. BGS

Explanation:

A marble dropped (initial vertical velocity is 0) will land at the same time as a marble launched horizontally (initial vertical velocity is 0) from the same height.

Boat S has a net speed of 5 m/s (10 − 5).

Boat B has a net speed of 15 m/s (10 + 5).

Boat G has a net speed of ≈11.2 m/s (√(10² + 5²)).

8 0

3 years ago

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Which single force acts on an object in free fall

ICE Princess25 [194]

Answer:

gravity

Explanation:

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3 years ago

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The effect produced when two or more sound waves pass through the same point simultaneously is called?

navik [9.2K]

The answer to the question is sound

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3 years ago

Which of the following is a category of mechanical wave?

givi [52]

Answer:

because the mechanical wave is when it goes over and over again

8 0

3 years ago

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A thin double convex glass lens with an index of 1.56 while surrounded by air has a 10 cm focal length. If it is placed under wa

bearhunter [10]

Explanation:

Formula which holds true for a leans with radii $R_{1}$ and $R_{2}$ and index refraction n is given as follows.

$\frac{1}{f} = (n - 1) [\frac{1}{R_{1}} - \frac{1}{R_{2}}]$

Since, the lens is immersed in liquid with index of refraction $n_{1}$ . Therefore, focal length obeys the following.

$\frac{1}{f_{1}} = \frac{n - n_{1}}{n_{1}} [\frac{1}{R_{1}} - \frac{1}{R_{2}}]$

$\frac{1}{f(n - 1)} = [\frac{1}{R_{1}} - \frac{1}{R_{2}}]$

and, $\frac{n_{1}}{f(n - n_{1})} = \frac{1}{R_{1}} - \frac{1}{R_{2}}$

or, $f_{1} = \frac{fn_{1}(n - 1)}{(n - n_{1})}$

$f_{w} = \frac{10 \times 1.33 \times (1.56 - 1)}{(1.56 - 1.33)}$

= 32.4 cm

Using thin lens equation, we will find the focal length as follows.

$\frac{1}{f} = \frac{1}{s_{o}} + \frac{1}{s_{i}}$

Hence, image distance can be calculated as follows.

$\frac{1}{s_{i}} = \frac{1}{f} - \frac{1}{s_{o}} = \frac{s_{o} - f}{fs_{o}}$

$s_{i} = \frac{fs_{o}}{s_{o} - f}$

$s_{i} = \frac{32.4 \times 100}{100 - 32.4}$

= 47.9 cm

Therefore, we can conclude that the focal length of the lens in water is 47.9 cm.

4 0

3 years ago