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OLga [1]
3 years ago
7

When the products of a reaction are hotter than the reactants: The reaction is exothermic. The reaction is endothermic. The reac

tants lost internal energy. The change in enthalpy is positive.
Chemistry
2 answers:
vodomira [7]3 years ago
6 0

Answer: Option (a) is the correct answer.

Explanation:

A chemical reaction in which energy is released is known as an exothermic reaction.

For example, A + B \rightarrow CD + Heat

In an exothermic reaction, energy of products is less than the energy of reactants. As heat is released that is why, formation of products become hotter.

On the other hand, a chemical reaction in which energy is absorbed by reactant molecules is known as an endothermic reaction.

For example, A + B + Heat \rightarrow CD

In an endothermic reaction, energy of products is more than the energy of reactants. As heat is absorbed, so formation of products become colder.

Thus, we can conclude that when the products of a reaction are hotter than the reactants the reaction is exothermic.

AlekseyPX3 years ago
3 0
<span>Exothermic reaction evolves energy due to which products get hot...</span>
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1. Draw a wedge/dash structure for trans-1,2-dimethylcyclohexane.
Angelina_Jolie [31]

Answer:

The structure with the ring flipped is the most stable

Explanation:

We have the  trans 1,2 - dimethylcyclohexane. With the wedge/dash structure we could not figure is this form is stable (If we do a comparison with the cis structure). But when we do a chair structure and ring flipped structure, this is easier to look.

The picture attached shows the structures, they are labeled as 1, 2 and 3, according to this problem.

In the chair structure, according to the picture below, you can see that both methyls are heading in the axial positions of the ring (One facing upward and the other downward). This is pretty stable, however, when the methyls are in those positions, the methyl position 1, can undergoes an 1,3 diaxial interactions with the hydrogens atoms (They are not drawn, but still are there), so this interaction makes this structure a little less stable that it can be.

On the other side, the ring flipped structure, we can see that both methyls are in the equatorials positions of the ring, and in these positions, it can avoid the 1,4 diaxial interactions with the hydrogens atoms, making this structure the most stable structure.

Hope this helps

6 0
3 years ago
A radioisotope decays to give an alpha particle andPb-208.
oee [108]

<u>Answer:</u> The original element is _{84}^{212}\textrm{Po}

<u>Explanation:</u>

Alpha decay is defined as the process in which alpha particle is emitted. In this process, a heavier nuclei decays into a lighter nuclei. The alpha particle released carries a charge of +2 units.

The released alpha particle is also known as helium nucleus.

_Z^A\textrm{X}\rightarrow _{Z-2}^{A-4}\textrm{Y}+_2^4\alpha

For the given alpha decay process of an isotope:

^{Z}_{A}\textrm{X}\rightarrow ^{208}_{82}\textrm{Pb}+_2^4\alpha

<u>To calculate A:</u>

Total mass on reactant side = total mass on product side

A = 208 + 4

A = 212

<u>To calculate Z:</u>

Total atomic number on reactant side = total atomic number on product side

Z = 82 + 2

Z = 84

The isotopic symbol of unknown element is _{84}^{212}\textrm{Po}

Hence, the original element is _{84}^{212}\textrm{Po}

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Explanation:

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