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OLga [1]
3 years ago
7

When the products of a reaction are hotter than the reactants: The reaction is exothermic. The reaction is endothermic. The reac

tants lost internal energy. The change in enthalpy is positive.
Chemistry
2 answers:
vodomira [7]3 years ago
6 0

Answer: Option (a) is the correct answer.

Explanation:

A chemical reaction in which energy is released is known as an exothermic reaction.

For example, A + B \rightarrow CD + Heat

In an exothermic reaction, energy of products is less than the energy of reactants. As heat is released that is why, formation of products become hotter.

On the other hand, a chemical reaction in which energy is absorbed by reactant molecules is known as an endothermic reaction.

For example, A + B + Heat \rightarrow CD

In an endothermic reaction, energy of products is more than the energy of reactants. As heat is absorbed, so formation of products become colder.

Thus, we can conclude that when the products of a reaction are hotter than the reactants the reaction is exothermic.

AlekseyPX3 years ago
3 0
<span>Exothermic reaction evolves energy due to which products get hot...</span>
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In a chemical reaction, ____ interact to form ____. select one:
QveST [7]
A. Reactants, products

In a chemical reaction, reactants interact to form products
7 0
3 years ago
Six moles of an ideal gas are in a cylinder fitted at one end with a movable piston. the initial temperature of the gas is 27.0c
Alla [95]

We have to know final temperature of the gas after it has done 2.40 X 10³ Joule of work.

The final temperature is: 75.11 °C.

The work done at constant pressure, W=nR(T₂-T₁)

n= number of moles of gases=6 (Given), R=Molar gas constant, T₂= Final temperature in Kelvin, T₁= Initial temperature in Kelvin =27°C or 300 K (Given).

W=2.4 × 10³ Joule (Given)

From the expression,

(T₂-T₁)=\frac{W}{nR}

(T₂-T₁)= \frac{2.40 X 10^{3} }{6 X 8.314}

(T₂-T₁)= 48.11

T₂=300+48.11=348.11 K= 75.11 °C

Final temperature is 75.11 °C.


6 0
3 years ago
How many grams of iron (Fe) will be produced if you start with 3.65 liters of carbon monoxide gas (CO) at STP?
iogann1982 [59]
The balanced equation for the above reaction is as follows;
<span>Fe</span>₂<span>O</span>₃<span> + 3 CO --> 2 Fe + 3 CO</span>₂
<span>stoichiometry of CO to Fe is 3:2
molar volume states that 1 mol of any gas occupies a volume of 22.4 L
If 22.4 L contains 1 mol of CO
Then 3.65 L contains - 1/22.4 x 3.65 = 0.16 mol 
3 mol of CO forms 2 mol of Fe
Then 0.16 mol of CO forms - 2/3 x 0.16 = 0.1067 mol of Fe
Therefore mass of Fe produced - 0.1067 mol x 55.8 g/mol = 5.95 g</span>
5 0
4 years ago
Which of the following statements regarding enzymes is FALSE? a. Enzymes alter the free energy change (ΔG) of the reactions whic
const2013 [10]

Answer:

Enzyme function is dependent on the three-dimensional structure or conformation of the enzyme

Explanation:

Enzyme are biological catalysts.

So they do alter the path of the reaction where the free energy change (or activation energy) is low then the non enzymatic pathway.

Thus the statement

Enzymes alter the free energy change (ΔG) of the reactions which they catalyze : True

It is known that for enzyme we function they need an optimum temperature and pH condition so the statement

Enzyme function is dependent on the pH and temperature of the reaction environment: true

This is also true that

Enzyme activity can be inhibited if the enzyme is bound by a noncompetitive inhibitor.

The false statement is : Enzyme function is dependent on the three-dimensional structure or conformation of the enzyme

6 0
3 years ago
A closed, frictionless piston-cylinder contains a gas mixture with the following composition on a mass basis: 40% carbon dioxide
Hitman42 [59]

Answer:

W=-37.6kJ, therefore, work is done on the system.

Explanation:

Hello,

In this case, the first step is to compute the moles of each gas present in the given mixture, by using the total mixture weight the mass compositions and their molar masses:

n_{CO_2}=0.8kg*0.4*\frac{1kmolCO_2}{44kgCO_2}= 0.00727kmolCO_2\\\\n_{O_2}=0.8kg*0.25*\frac{1kmolO_2}{32kgO_2}=0.00625kmolO_2\\ \\n_{Ne}=0.8kg*0.35*\frac{1kmolNe}{20.2kgNe}=0.0139kmolNe

Next, the total moles:

n_T=0.00727kmol+0.00625kmol+0.0139kmol=0.02742kmol

After that, since the process is isobaric, we can compute the work as:

W=P(V_2-V_1)

Therefore, we need to compute both the initial and final volumes which are at 260 °C and 95 °C respectively for the same moles and pressure (isobaric closed system)

V_1=\frac{n_TRT_1}{P}= \frac{0.02742kmol*8.314\frac{kPa*m^3}{kmol\times K}*(260+273)K}{450kPa}=0.27m^3\\ \\V_2=\frac{n_TRT_2}{P}= \frac{0.02742kmol*8.314\frac{kPa*m^3}{kmol\times K}*(95+273)K}{450kPa}=0.19m^3

Thereby, the magnitude and direction of work turn out:

W=450kPa(0.19m^3-0.27m^3)\\\\W=-37.6kJ

Thus, we conclude that since it is negative, work is done on the system (first law of thermodynamics).

Regards.

7 0
3 years ago
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