Find f'(x) if f(x)=3squareroot(x+2)using the definition of the derivative!

Mathematics

1 answer:

ycow [4]3 years ago

4 0

I hope this helps you

f (x)=(x+2)^3/2

f'(x)=3/2. (x+2)^3/2-1

f'(x)=3/2 (x+2)^1/2

f'(x)=3/2.square root of (x+2)

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Gemiola [76]

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PLEASE HELP! 50 Points!

gulaghasi [49]

The bearing of the plane is approximately 178.037°. $\blacksquare$

<h3>Procedure - Determination of the bearing of the plane</h3><h3 />

Let suppose that <em>bearing</em> angles are in the following <em>standard</em> position, whose vector formula is:

$\vec r = r\cdot (\sin \theta, \cos \theta)$ (1)

Where:

$r$ - Magnitude of the vector, in miles per hour.
$\theta$ - Direction of the vector, in degrees.

That is, the line of reference is the $+y$ semiaxis.

The <em>resulting</em> vector ( $\vec v$ ), in miles per hour, is the sum of airspeed of the airplane ( $\vec v_{A}$ ), in miles per hour, and the speed of the wind ( $\vec v_{W}$ ), in miles per hour, that is:

$\vec v = \vec v_{A} + \vec v_{W}$ (2)

If we know that $v_{A} = 239\,\frac{mi}{h}$ , $\theta_{A} = 180^{\circ}$ , $v_{W} = 10\,\frac{m}{s}$ and $\theta_{W} = 53^{\circ}$ , then the resulting vector is: