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NemiM [27]
3 years ago
11

How much heat in joules is required to melt an ice cube with a mass of 18.6 g at 0 °C? The Lf for water is 333 J/g.

Physics
1 answer:
EastWind [94]3 years ago
5 0

Answer:

The heat energy required, Q = 6193.8 J

Explanation:

Given,

The mass of ice cube, m = 18.6 g

The heat of fusion of ice, ΔHₓ = 333 J/g

The heat energy of a substance is equal to the product of the mass and heat of fusion of that substance. It is given by the equation,

                               <em> Q = m · ΔHₓ     joules</em>

Substituting the given values in the above equation

                                Q = 18.6 g x 333 J/g

                                    = 6193.8 J

Hence, the heat required to melt the ice cube is, Q = 6193.8 J

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Two people push on the same door from opposite sides as shown.
tangare [24]
The correct answer is
<span>c. one person exerts more force than the other so that the forces are unbalanced.

In fact, the door is initially at rest. In order to move the door, a net force different from zero should be applied, according to Newton's second law:
</span>\sum F = ma
<span>where the term on the left is the resultant of the forces acting on the door, m is the door mass and a its acceleration.

In order to move the door, the acceleration must be different from zero. But this means that the resultant of the forces acting on it must be different from zero: this is possible only if  the forces applied by the two persons are unbalanced, i.e. one person exerts more force than the other.</span>
3 0
2 years ago
Read 2 more answers
Electronics and inhabitants of the International Space Station generate a significant amount of thermal energy that the station
katrin2010 [14]

Answer:

4462.0927 W

Explanation:

\epsilon = Emissivity of the panel = 1

\sigma = Stefan-Boltzmann constant = 5.67\times 10^{-8}\ W/m^2K^4

T = Temperature = (273.15+6)

Area of the panel is given by

A=2\times 1.8\times 3.6\\\Rightarrow A=12.96\ m^2

The power radiated is given by

P=\epsilon \sigma AT^4\\\Rightarrow P=1\times 5.67\times 10^{-8}\times 12.96\times (273.15+6)^4\\\Rightarrow P=4462.0927\ W

The power radiated from each panel is 4462.0927 W

5 0
3 years ago
Which type of energy releases greenhouse gases when used to make electricity?
Elan Coil [88]
A) Geothermal
B) Hydroelectric
C)Biomass
D) Wind

I assume this is the four options you had, correct?

i think that biomass is the only one that would release the greenhouse gases. I once heard, it may not be true, that biomass has more co2 released than coal.
4 0
3 years ago
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An astronaut on a strange planet finds that she can jump a maximum horizontal distance of 14.0 m if her initial speed is 2.20 m/
pochemuha

We have the equation of motion

                          v^2 = u^2+2as , where v is the final velocity, u is the initial velocity, a is the acceleration and s is the displacement.

In this case initial velocity = 2.20 m/s, final velocity = 0 m/s, displacement = 14 m

On substitution we will get 0 = 2.20^2+2*a*14

On solving we can find the acceleration value as -0.173m/s^2

So free fall acceleration = 0.173m/s^2

                                             


3 0
3 years ago
Coherent light with wavelength 610 nm passes through two very narrow slits, and theinterference pattern is observed on a screen
andriy [413]

Answer:

= 1220 nm

= 1.22 μm

Explanation:

given data:

wavelength \lambda = 610 nm = 610\times  10 ^{-9} m

distance of screen from slits D = 3 m

1st order bright fringe is 4.84 mm

condition for 1 st bright is

d sin \theta =\lambda     ---( 1)

andtan \theta = \frac{y}{ D}

\theta = tan^{-1}\frac{(y }{D})

= 0.0924 degrees

plug theta value in equation 1 we get

d sin ( 0.0924) = 610 \times 10 ^{-9}

d = 3.78\times 10^{-4} m

condition for 1 st dark fringe

d sin \theta =\frac{λ'}{2}

\lambda '= 2 d sin\theta

= 2λ    since from eq (1)

= 1220 nm

= 1.22 μm

7 0
3 years ago
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