The part of the electromagnetic spectrum has a shorter wavelength than ultraviolet light is x-rays.
Answer:
c. both have same energy
Explanation:
The complete question is
suppose you have two cans, one with milk, and the other with refried beans. The cans have essentially the same size, shape, and mass. If you release both cans at the same time, on a downhill ramp, which can has more energy at the bottom of the ramp? ignore friction and air resistance..
a. can with beans
b. can with milk
c. both have same energy
please explain your answer
Since both cans have the same size, shape, and mass, and they are released at the same height above the ramp, they'll possess the same amount of mechanical energy. This is because their mechanical energy, which is the combination of their potential and kinetic energy are both dependent on their mass. Also, having the same physical quantities like their size and shape means that they will experience the same environmental or physical factors, which will be balanced for both.
Einstein's energy mass equivalence relation say that if the whole given mass is converted to energy then it would be
where
m = mass in kg
c = speed of light in m/s
this is the origination of quantum physics and by this formula we can relate the dual nature of light and particle
So correct relation above will be
Becomes older
Explanation:
As sea floor spreading occurs at divergent margins, the oceanic plate becomes older. Younger plate margin are the closest to the margin whereas the older plates bushes backward away from the spreading centers.
- The idea that the sea floor spreads was postulated by Harry Hess shortly after the second world war around the 1960's.
- At divergent margins new crust materials from the mantle are brought to the surface.
- They crystallize and settle at the flanks of plate margins.
- Older ones are pushed backward away from the margin into far away subduction zones.
Learn more:
Sea floor spreading brainly.com/question/9912731
#learnwithBrainly
Answer:
<h3> b. 1.18</h3>
Explanation:
The fundamental frequency in string is expressed as;
F1 = 1/2L√T/m .... 1
L is the length of the string
T is the tension
m is the mass per unit length
If the tension is increased by 40%, the new tension will be;
T2 = T + 40%T
T2 = T + 0.4T
T2 = 1.4T
The new fundamental frequency will be;
F2 = 1/2L√1.4T/m ..... 2
Divide 1 by 2;
F2/F = (1/2L√1.4T/m)/1/2L√T/m)+
F2/F = √1.4T/m ÷ √T/m
F2/F = √1.4T/√m ×√m/√T
F2/F = √1.4T/√T
F2/F = 1.18√T/√T
F2/F = 1.18
F2 = 1.18F
Hence the fundamental frequency of vibration changes by a factor of 1.18
