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Vesnalui [34]
3 years ago
6

When a tuning fork vibrates over an open pipe and the air in the pipe starts to vibrate, the vibrations in the tube are caused b

y
a. harmonics.
b. beats.
c. reinforcement.
d. resonance.
Physics
2 answers:
Mkey [24]3 years ago
4 0
The correct response is D.

Gemiola [76]3 years ago
3 0

When a tuning fork vibrates over an open pipe and the air in the pipe starts to vibrate, the vibrations in the tube are caused by:

d. resonance.

When the tuning fork vibrates near the open end of the cylinder, the sound waves from the fork are sent into the pipe. When one object vibrates, it forces another object to vibrate at the same frequency and this is called resonance .

Explanation:

In physics, resonance is an event in which a vibrating system or external force drives different system to vibrate with greater amplitude at particular frequencies. Frequencies at which the response amplitude is a relative peak are known as the system's resonant frequencies or resonance frequencies.

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Yuliya22 [10]

Answer:

12 km/h

Explanation:

Average Speed = Distance / Time (or rate)

Pick a point on the graph for Ian and plug in values.

For example, 20 minutes -> 4km

Hence, Average speed = 4km ÷ 20 minutes = 0.2 km/min

0.2 km/min × 60 = 12 km/h

7 0
3 years ago
Read 2 more answers
Một chất điểm DĐĐH có phương trình x=Acos(omega t). Tìm thời gian chất điểm qua vtcb theo chiều dương lần thứ 2?
Arada [10]

Answer:

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8 0
3 years ago
Assignment 10 Coulombic Equation Practice Directions: Complete the following problems to calculate the electrostatic force that
Tatiana [17]

Answer:

Magnitude of the force between the charges is F = 1.92×10^20N

Explanation:

Given the magnitude of force according to coulombs law

F =K[(q1*q2)/r2]

Where q1 and q2 are the charges

r is the distance between the charges

K is the coulombs constant

Substituting the given values, we have;

F = 8.98×10^9 × 1.5×10^6 × 3.2×10^4/1.5²

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8 0
3 years ago
A force is applied to the rim of a disk that can rotate like a merry-go-round, so as to change its angular velocity. Its initial
yawa3891 [41]

Answer:

A = B = C > D

Explanation:

Work done to stop the disc is given as

W = \Delta K

W = \frac{1}{2}I(\omega_f^2 - \omega_i^2)

so we have

(a) –2 rad/s, 5 rad/s;

(b) 2 rad/s, 5 rad/s;

(c) –2 rad/s, –5 rad/s; and

(d) 2 rad/s, –5 rad/s.

So we have

W_a = W_b = W_c = \frac{1}{2}I(5^2 - 2^2)

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so we have

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5 0
2 years ago
Rahman drops two stones P and Q each of mass 1 kg and 2 kg simultaneously from
kolbaska11 [484]

This question involves the use of the equations of motion for vertical motion.

The time taken by the stones P and Q to reach the ground is the same, that is "2 s".

The velocity with which Q hits the ground is "20 m/s".

The time taken by the stones to reach the ground can be calculated by using the second equation of motion for the vertical motion:

h = v_it+\frac{1}{2}gt^2

For both the stones P and Q:

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t = time = ?

g = acceleration due to gravity = 10 m/s²

Therefore,

20\ m = (0\ m/s)t+\frac{1}{2}(10\ m/s^2)(t)^2\\\\t = \sqrt{\frac{20\ m}{5\ m/s^2}}

<u>t = 2 s</u>

<u></u>

Hence, the time taken by both the stones to reach the ground <u>is the same</u>.

To find the final velocity of stone Q we will use the first equation of motion for the vertical motion:

v_f=v_i+gt\\v_f = 0\ m/s+(10\ m/s^2)(2\ s)\\v_f = 20\ m/s

Learn more about equations of motion here:

brainly.com/question/20594939?referrer=searchResults

The attached picture shows the equations of motion in the horizontal and vertical directions.

5 0
2 years ago
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