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Vesnalui [34]
3 years ago
6

When a tuning fork vibrates over an open pipe and the air in the pipe starts to vibrate, the vibrations in the tube are caused b

y
a. harmonics.
b. beats.
c. reinforcement.
d. resonance.
Physics
2 answers:
Mkey [24]3 years ago
4 0
The correct response is D.

Gemiola [76]3 years ago
3 0

When a tuning fork vibrates over an open pipe and the air in the pipe starts to vibrate, the vibrations in the tube are caused by:

d. resonance.

When the tuning fork vibrates near the open end of the cylinder, the sound waves from the fork are sent into the pipe. When one object vibrates, it forces another object to vibrate at the same frequency and this is called resonance .

Explanation:

In physics, resonance is an event in which a vibrating system or external force drives different system to vibrate with greater amplitude at particular frequencies. Frequencies at which the response amplitude is a relative peak are known as the system's resonant frequencies or resonance frequencies.

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During which phase of the moon may a lunar eclipse occur?
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Answer: New moon

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Slick Willy is in traffic court (again) contesting a $50.00 ticket for running a red light. “You see, your Honor, as I was appro
natta225 [31]

Answer and Explanation:

Greetings!

I'm~Isabelle~Williams~and~I~will~be~answering~your~question!

Given:

Wave~length~ of~  red ~ light = 683~  nm

Wave ~length ~of~ yellow~ light = 576~ nm

The~ speed ~of~ the~ Slick~ Willy~ can~ be:

\boxed{~f'=(\frac{v+v_{o} }{v} )f~}

Where:

f'=observed~frequency

f=actual~frequency

v=speed~of~light

v_{o}=~speed~of~observer

Plug~in~the~values:

683\times 10^-^9=576\times 10^-^9 ~(1+\frac{v_{o} }{3\times 10^8} )

\frac{683}{576}=1+\frac{v_{o} }{3\times 10^8}

\frac{v_{o} }{3\times 10^8}  =\frac{683}{576}=-1

v_{o}=0.186\times 3\times 10^8

v_{o}=0.558\times 10^8 ~m/s

Hope~this~helps!~Have~an~amazing~day~ahead!~

-Isabelle~Williams

6 0
4 years ago
The choices are
Anettt [7]

Answer:

C

Explanation:

7 0
3 years ago
. A driver travels 4.25 km. in two minutes. If the driver’s initial velocity is 20m/s, what is the acceleration?
Novosadov [1.4K]

Answer:

32.9166667 m / s^2

Explanation:

s = 4.25km (1000m / 1km)

= 4250m

u = 20m/s

delta T = 20min (60sec / 1min)

= 1200s

Use formula s = ut + (1/2)at^2

4250m = 20m/s * 1200s + (1/2)a*1200s^2

Rearrange it to find a

a = (s-ut)  / (1/2 * t^2)

a = (4250m - 20m/s*1200s) / (1/2 * 1200s^2)

a = -32.9166667 m / s^2

4 0
3 years ago
Momentum is a scalar quantity.<br>True or false​
Rudiy27
The answer is false
5 0
3 years ago
Read 2 more answers
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