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Maru [420]
3 years ago
5

A satellite is orbiting the earth. If a payload of material is added until it doubles the satellite's mass, the earth's pull of

gravity on this satellite will double but the satellite's orbit will not be affected.
a. True
b. False
Physics
2 answers:
FromTheMoon [43]3 years ago
8 0

Answer:

true

Explanation:

The orbit of satellite does not depends on the mass of satellite.

As teh gravitational force between the earth and the satellite is balanced by the centripetal force.

So, mass of satellite cancels out from both the sides.

Thus, the satellite orbit will not be affected by the doubling the mass of teh satellite.

So, the statement is true.

dimulka [17.4K]3 years ago
6 0

Answer:

True

Explanation:

When a satellite is orbiting the earth, the centripetal force is balanced by the gravitational force as :

\dfrac{GMm}{r^2}=\dfrac{mv^2}{r}

v=\sqrt{\dfrac{GM}{r}}...........(1)

Where

M is the mass of the earth

m is the mass of the planet

From equation (1), the speed of the satellite depends only on the mass of the earth and the orbital radius.

So, If a payload of material is added until it doubles the satellite's mass, the earth's pull of gravity on this satellite will double but the satellite's orbit will not be affected. It is true.

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A proton is held at rest in a uniform electric field. When it is released, the proton will lose?
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A narrow region between two air masses of different densities is a
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Many of water's emergent properties, such as its cohesion, its high specific heat, and its high heat of vaporization, result fro
Bingel [31]

Answer:

Option 5.

Explanation:

Many of the properties of water like high specific heat, cohesion, high vaporization heat, etc can be contributed to the polar nature of water molecule.

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3 0
3 years ago
Consider two sizes of disk, both of mass M. One size of disk has radius R; the other has radius 4R. System A consists of two of
Harman [31]

Answer:

4 smaller disks

Explanation:

We are given;

Mass of smaller and larger disks = M

Radius of smaller disk = R

Radius of larger disk = 4R

Formula for moment of inertia about cylinder axis is:

I = ½MR²

Thus;

For small disk, I_small = ½MR²

For large disk, I_large = ½M(2R)² = 2MR²

We are told that moment of inertia of System A consists of two of the larger disks. Thus;

I_A = 2 × I_large = 2 × 2MR²

I_A = 4MR²

We are also told that System B consists of one of the larger disks and a number of the smaller disks. Thus;

I_B = I_large + n(I_small)

Where n is the number of smaller disks.

I_B = 2MR² + n(½MR²)

I_B = MR²(2 + n/2)

We are told that the moment of inertia for system A equals the moment of inertia for system B. Thus;

I_A = I_B

So;

4MR² = MR²(2 + n/2)

MR² will cancel out to give;

4 = 2 + n/2

Multiply through by 2 to give;

8 = 4 + n

n = 8 - 4

n = 4

5 0
3 years ago
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