Velocity = distance/time
v = (35)/(1/2)
v = 70 km/h
60 km/h for 25 minutes
25 minutes = 25/60 hour
distance= velocity * time
d =(60) * (25/60)
d = 25 km
ΔV = { V(initial) - V(final) } / time
v= (70-60) / (45/60)
average velocity = 13.33 km/h
avg veloticy = 3.7 m/s
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These are the Kepler's laws of planetary motion.
This law relates a planet's orbital period and its average distance to the Sun. - Third law of Kepler.
The orbits of planets are ellipses with the Sun at one focus. - First law of Kepler.
The speed of a planet varies, such that a planet sweeps out an equal area in equal time frames. - Second law of Kepler.
When light passes from a faster medium into a slower medium, light will be refracted toward a line drawn perpendicular to the point of refraction. <em>(B)</em>
Answer:
Explanation:
Please find the image for the question as attached file.
Solution -
Given -
First of all we will calculate the velocity at point C,
As per newton's third law of motion-
Substituting the given values in above equation, we get -
Now we will determine the radius of curvature for the curve shown in the attached image
Differentiating on both the sides, we get -
![\frac{dy}{dx} = -3.2 (10^-3) X\\\frac{d^2y}{d^2x} = -3.2 (10^-3)\\Curve = \frac{[1+(\frac{dy}{dx})^2]^{\frac{3}{2}} }{\frac{d^2y}{d^2x}} \\Curve = 312.5](https://tex.z-dn.net/?f=%5Cfrac%7Bdy%7D%7Bdx%7D%20%3D%20-3.2%20%2810%5E-3%29%20X%5C%5C%5Cfrac%7Bd%5E2y%7D%7Bd%5E2x%7D%20%3D%20%20-3.2%20%2810%5E-3%29%5C%5CCurve%20%3D%20%5Cfrac%7B%5B1%2B%28%5Cfrac%7Bdy%7D%7Bdx%7D%29%5E2%5D%5E%7B%5Cfrac%7B3%7D%7B2%7D%7D%20%20%7D%7B%5Cfrac%7Bd%5E2y%7D%7Bd%5E2x%7D%7D%20%5C%5CCurve%20%3D%20312.5)
meter
Acceleration on curved path
Final acceleration
Getting someone to help you push your car out of a snowdrift. You both get on the same end of it and push in the same direction. Another beautiful example is a Tug-o-War, where you might have 50 people (!) all exerting force on the rope in the same direction.
