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Oksana_A [137]
3 years ago
6

How can we define force?

Physics
2 answers:
mars1129 [50]3 years ago
8 0

Answer:

There are 2 definitions chose the suitable one for ur question

Explanation:

1. strength or energy as an attribute of physical action or movement.

2. coercion or compulsion, especially with the use or threat of violence.

HOPE THIS HELPS

zimovet [89]3 years ago
4 0

Explanation:

A force is a push or pull upon an object resulting from the object's interaction with another object. Whenever there is an interaction between two objects, there is a force upon each of the objects. When the interaction ceases, the two objects no longer experience the force.

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When discussing distances between objects in the solar system, which term do you use?
Bond [772]
I think it's (ASTRONOMICAL UNIT)

Explanation:
It is used to compare the distances of other bodies in the Solar System, such as the Sun, the planets, comets, and asteroids.
8 0
2 years ago
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It is common problem to a physically active person who is experiencing dizziness, fatigue, dark-colored urine, and extreme thirs
choli [55]

Answer:

Look below.

Explanation:

All the symptoms provided points to the common problem of dehydration. Especially a physically active person because they are constantly sweating which leads to the loss of bodily fluids and dehydration.

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3 years ago
A constant net torque is exerted on an object. Which of the following quantities for the object cannot be constant? (Select all
prohojiy [21]

Answer:

A. kinetic energy

B. angular velocity

E. angular position

Explanation:

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B. Angular velocity. It will change at a rate equal to the torque.

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3 0
4 years ago
Suppose you wish to fabricate a uniform wire from a mass m of a metal with density rhom and resistivity rho. If the wire is to h
slamgirl [31]

Answer:

Explanation:

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R=\frac{L}{A}\rho

furthermore, the density is the mass divided by the volume, and the volume can be written as the area multiplyed by the length:

\rho_m=\frac{m}{A*L}

Now you have tw equations and two variables, so you can solve for each of them.

first, solve for A in both equations and replace them:

\frac{L}{R}\rho=\frac{m}{\rho_mL}

L^2=\frac{mR}{\rho_m \rho} \\L=

now replace this into any of the previous equiations:

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If you assume the wire has circular cross-sectional area, then the area is:

A=\pi(\frac{d}{2} )^2

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d=2\sqrt{\frac{A}{\pi} }

replacing A and simplifying:

d=2 \sqrt[4]{\frac{m\rho}{\rho_m R \pi^2} }

5 0
3 years ago
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