Question

An object is thrown upward from the top of a 128​-foot building with an initial velocity of 112 feet per second. The height h of the object after t seconds is given by the quadratic equation h equals negative 16 t squared plus 112 t plus 128. When will the object hit the​ ground?

Answer 1

Answer:

Time, t = 8 seconds

Explanation:

An object is thrown upward from the top of a 128​-foot building with an initial velocity of 112 feet per second. The height h as a function of time t is given by :

$h=-16t^2+112t+128$

We need to find the time when the object will hit the ground. When it will hit the ground, h = 0

So,

$-16t^2+112t+128=0$

On solving the above quadratic equation, we get the value of t = 8 seconds. So, after 8 seconds the object will hit the ground. Hence, this is the required solution.