All categories

3 years ago

Balance the combustion reaction between butane and oxygen. 2C4H10 + O2 → CO2 + H2O

Chemistry

2 answers:

dimaraw [331]3 years ago

6 0

<h2>Answer:</h2><h3>Balanced equation:</h3>

2C4H10 + 8O2 → 8CO2 + 10H2O

<h3>Description:</h3>

There should be 8 molecules of oxygen which react with 2 molecules of butane to produce 8 molecules of carbon dioxide and 10 molecules of water.

pashok25 [27]3 years ago

4 0

Answer:

Explanation:

Answer:

2C4H10 + 13O2 → 8CO2 + 10H2O

Explanation:

2C4H10 + O2 → CO2 + H2O

There are 8 carbon atoms on the left side of the equation thus , there should be equal number of carbon atoms on the right side

So, if we balance carbon atoms only, the new eqation becomes

2C4H10 + O2 → 8CO2 + H2O

Now carbon atoms are balance but there are 20 , hydrogen atoms on the left side but 2 atoms only on the right side. So the new equation after balancing hydrogen atom becomes

2C4H10 + O2 → 8CO2 + 10H2O

Now both carbon and hydrogen atoms are balanced but oxygen atoms are pending. There are 26 atoms of (O) on the right side , while 1 molecule of (O2)

So the balanced equation would be

2C4H10 + 13O2 → 8CO2 + 10H2O

You might be interested in

1. list at least two possible sources of error from the experiment. would these errors result in an overestimation or an underes

quester [9]

An error in estimation could arise owing to;

1) Inaccurate measurement of the volumes of the solutions

2) When the reaction vessels are not properly cleaned

<h3>What is error in an experiment?</h3>

Error could occur in an experiment when values are misread. The error could be random error or a systematic error.

The major ways in which an error can occur in the estimation of concentration of acetic acid in the vinegar are;

1) Inaccurate measurement of the volumes of the solutions

2) When the reaction vessels are not properly cleaned

Learn more about errors in experiment:brainly.com/question/14149934

#SPJ1

6 0

2 years ago

g 304 mL of a 0.36 M potassium hydroxide solution is added to 341 mL of a 0.51 M lithium hydroxide solution. Calculate the pOH o

Liono4ka [1.6K]

Answer:

pOH = 0.36

Explanation:

Both potassium hydroxide and lithium hydroxide solutions are strong bases, so you assume 100% dissociation.

1. Potassium hydroxide solution, KOH

Volume, V = 304 mL = 0.304 liter

Molarity, M = 0.36 M

number of moles, n = M × V = 0.36M × 0.304 liter = 0.10944 mol

1 mole of KOH produces 1 mol of OH⁻ ion, thus the number of moles of OH⁻ is 0.10944

2. LIthium hydroxide, LiOH

Volume, V = 341 mL = 0.341 liter

Molarity, M = 0.51 M

number of moles, n = M × V = 0.341 liter × 0.51 M = 0.17391 mol

1mole of LiOH produces 1 mol of OH⁻ ion, thus the number of moles of OH⁻ is 0.17391

3. Resulting solution

Number of moles of OH⁻ ions = 0.10944 mol + 0.17391 mol = 0.28335 mol

Volume of solution = 0.304 liter + 0.341 liter = 0.645 liter

Molar concentration = 0.28335 mol / 0.645 liter = 0.4393 M

4. pOH

$pOH=-\log [OH^-]=-\log (0.439)=0.36$ ← answer

5 0

3 years ago

AgNO3 + NaCl mc017-1.jpg NaNO3 + AgCl

lina2011 [118]

The balanced reaction is:

AgNO3 + NaCl = NaNO3 + AgCl

We are given the amount of silver nitrate to react with sodium chloride. This will be our starting point.

15.0 mol AgNO3 (1 mol AgCl / 1 mol AgNO3 ) =15.0 mol AgCl

The amount of moles produced is the same with the amount of the given reactant since they only one is to one ratio.

8 0

4 years ago

Read 2 more answers

Calculate the mass of each product formed when 84.3 g of silver sulfide reacts with excess hydrochloric acid: ag2s(s) + hcl(aq)

oee [108]

Answer:

48.75 g of AgCl

11.60 g of H₂S

Solution:

The Balance Chemical Equation is as follow,

Ag₂S + HCl → AgCl + H₂S

Calculate amount of AgCl produced,

According to equation,

247.8 g (1 mol) of Ag₂S produces = 143.32 g (1 mol) of AgCl

So,

84.3 g of Ag₂S will produce = X g of AgCl

Solving for X,

X = (84.3 g × 143.32 g) ÷ 247.8 g

X = 48.75 g of AgCl

Calculate amount of H₂S produced,

According to equation,

247.8 g (1 mol) of Ag₂S produces = 34.1 g (1 mol) of H₂S

So,

84.3 g of Ag₂S will produce = X g of H₂S

Solving for X,

X = (84.3 g × 34.1 g) ÷ 247.8 g

X = 11.60 g of H₂S

6 0

3 years ago

A chemist needs to neutralize 25.5 L of 3.86 M chloric acid (HClO3). What mass of sodium hydroxide is

Karolina [17]

Answer:

3.94 × 10³ g

Explanation:

Step 1: Write the neutralization reaction

HClO₃ + NaOH = NaClO₃ + H₂O

Step 2: Calculate the moles of chloric acid that react

25.5 L of 3.86 M chloric acid is to be neutralized. The reacting moles are:

$25.5L \times \frac{3.86mol}{L} =98.4mol$

Step 3: Calculate the required moles of sodium hydroxide

The molar ratio of HClO₃ to NaOH is 1:1. Then, the reacting moles of NaOH are 98.4 moles.

Step 4: Calculate the mass of sodium hydroxide corresponding to 98.4 moles

The molar mass of NaOH is 40.00 g/mol.

$98.4mol \times \frac{40.00g}{mol} =3.94 \times 10^{3} g$

6 0

3 years ago