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3 years ago

Balance the combustion reaction between butane and oxygen. 2C4H10 + O2 → CO2 + H2O

Chemistry

2 answers:

dimaraw [331]3 years ago

6 0

<h2>Answer:</h2><h3>Balanced equation:</h3>

2C4H10 + 8O2 → 8CO2 + 10H2O

<h3>Description:</h3>

There should be 8 molecules of oxygen which react with 2 molecules of butane to produce 8 molecules of carbon dioxide and 10 molecules of water.

pashok25 [27]3 years ago

4 0

Answer:

Explanation:

Answer:

2C4H10 + 13O2 → 8CO2 + 10H2O

Explanation:

2C4H10 + O2 → CO2 + H2O

There are 8 carbon atoms on the left side of the equation thus , there should be equal number of carbon atoms on the right side

So, if we balance carbon atoms only, the new eqation becomes

2C4H10 + O2 → 8CO2 + H2O

Now carbon atoms are balance but there are 20 , hydrogen atoms on the left side but 2 atoms only on the right side. So the new equation after balancing hydrogen atom becomes

2C4H10 + O2 → 8CO2 + 10H2O

Now both carbon and hydrogen atoms are balanced but oxygen atoms are pending. There are 26 atoms of (O) on the right side , while 1 molecule of (O2)

So the balanced equation would be

2C4H10 + 13O2 → 8CO2 + 10H2O

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On the table below, record your observations before and after the interactions and note if mass was conserved. Describe the chan

lilavasa [31]

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Egg + Heat The egg has a yellow yolk in the middle while there is some type of liquid at the border of the yolk, but it is clear, the heat is hot but transparent The egg turned into a delicious food called an omelet what was yolk staid as a liquid but got a tad harder, but the transparent border around it turned white It was conserved because the eggshell was 4 grams and the fried egg is 41 grams It is a chemical change because it results in the formation of new particles, and the chemical bonds break up and new ones are formed.

Water + Heat The water is a clear liquid, while the heat is very hot but transparent The water turned into a type of oxygen -Water Vapor- If 5 g of water becomes a gas it becomes 5 g of water vapor. The mass of the liquid water is simply transferred into the mass of the newly formed water vapor. There was no chemical reaction because the water vapor can be turned back to water also it just changed from a liquid to a gas and did not change its composition

Zinc + Hydrogen Chloride Zinc: a white/silver metallic solid. Hydrogen chloride (dilute hydroelectric acid) a transparent, colorless liquid with a very low pH (acidic). Zinc "dissolved" in hydrogen chloride, while emitting a colorless gas. The liquid remains a colorless liquid, possibly still having a low pH from the unused acid. The colorless gas collected in a test tube gives a popping sound when ignited with a burning wooden splint, so it is not air embedded in the zinc, nor dissolved in hydroelectric acid. Well although the zinc chloride is 12 grams and not 15 the gas that was released was 3 grams and as we all know 3 + 12 is 15 so you could say that the mass was conserved The production of a new substance (most probably hydrogen) from the reaction of the two reactants. When a few drops of the liquid product are evaporated on a watch glass, a white residue is left. When a few drops of the liquid hydroelectric acid are evaporated on a watch glass, there is no residue. This proves that a new product (hydrogen gas), (white powder, zinc chloride) is produced instead of zinc being physically dissolved in hydroelectric acid.

Sodium Hydroxide + Copper Sulfate Sodium hydroxide is a turbid solution and copper sulfate is in form of bright blue crystals. When their solutions are mixed with each other, a pale blue precipitate of basic copper hydroxide & a solution of neutral salt sodium sulfate will be formed. The sodium hydroxide and the copper sulfate combined make a total of 67 grams and the product is split because the sodium sulfate is 47 grams and the copper hydroxide is 20 grams but all together it is still 67 grams so you could say that the mass was conserved The proof of the reaction is the appearance of pale blue precipitates of basic copper hydroxide & a solution of neutral salt sodium sulfate.

5 0

3 years ago

Gallium chloride is formed by the reaction of 2.25 L of a 1.50 M solution of HCl according to the following equation: 2Ga 6HCl -

Setler79 [48]

Answer:

198.56g of GaCl3

Explanation:

We'll begin by calculating the number of mole HCl in 2.25 L of a 1.50 M solution of HCl. This is illustrated below:

Molarity of HCl = 1.50 M

Volume = 2.25 L

Mole of HCl =..?

Molarity = mole /Volume

1.5 = mole /2.25

Cross multiply

Mole = 1.5 x 2.25

Mole of HCl = 3.375 mole

Next, we shall determine the number of mole Gallium chloride, GaCl3 produced from the reaction. This is shown below:

2Ga + 6HCl —> 2GaCl3 + 3H2

From the balanced equation above,

6 moles of HCl reacted to produce 2 moles of GaCl3.

Therefore, 3.375 mole of HCl will react to produce = (3.375 x 2)/6 = 1.125 mole of GaCl3.

Therefore, 1.125 moles of GaCl3 were produced from the reaction.

Next, we shall convert 1.125 mole of GaCl3 to grams. This is illustrated below:

Molar mass of GaCl3 = 70 + (35.5x3) = 176.5g/mol

Mole of GaCl3 = 1.125 mole

Mass of GaCl3 =..?

Mole = mass /Molar mass

1.125 = mass of GaCl3 /176.5

Cross multiply

Mass of GaCl3 = 1.125 x 176.5

Mass of GaCl3 = 198.56g

Therefore, 198.56g of GaCl3 were produced from the reaction.

7 0

3 years ago

A coffee-cup calorimeter initially contains 125 g water at 24.28C. Potassium bromide (10.5 g), also at 24.28C, is added to the w

iren2701 [21]

Answer:

The solution is given below

Explanation:

Heat, q= mc∆T

q= 125g x 4.18 J/g∙°C x (21.18x- 24.28) °C

q= -1619.75J

NEGATIVE SIGN INDICATES THAT HEAT IS ABSORBED.

Enthalpy Change, ∆H = 1619.75 7/ 10.5 g

= 154.26 J/g

No. of moles of KBr = Mass of KBr/ Molecular Weight of KBr

=10.5g/119gmol-1

=0.088 mol

∆H= 1619.75 J/ 0.088 mol

= 18.41 kJ/mol

6 0

3 years ago

Concentration of 10.00 mL of HBr if it takes 5 mL of a 0.253 M LiOH solution to<br> neutralize it?

Sonbull [250]

In a titration, for an acid to neutralize a base, at the equivalence point, there should be an equal number of moles of H+ and OH-.

Moles of OH- can be found by multiplying the concentration of the base by the volume. (You will need to keep in mind the stoichimetric coefficients if the strong base is Ca(OH)₂, Ba(OH)₂, or Sr(OH)₂.

Moles of OH- = moles of H+
(0.253 M) * 0.005 L = 0.01000 L * c
c = 0.1265 M

The concentration of HBr is 0.127 M.

3 0

3 years ago

2. What is the mass of 5.33 x 10 moles of aluminum hydroxide?

bearhunter [10]

<h3>Answer:</h3><h3>1865.5g</h3><h3>Explanation:</h3><h3 /><h2> first the chemical formular for ammonium hydroxide is NH4OH</h2><h3>its molarmass is given as N=14H=1O=16 </h3><h3> so we have 14 +1(2) +16+1 =35</h3><h2>also no of moles = mass / molarmass</h2><h3> we have 5.33×10 = mass/35 </h3><h2>therefore mass = 35 ×5.33×10 = 1865.5g</h2>

8 0

2 years ago