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alina1380 [7]
4 years ago
5

How many hydrogen atoms are in 7.80 mol of ammonium sulfide?

Chemistry
2 answers:
Alexus [3.1K]4 years ago
7 0

The number  of hydrogen atoms that are in 7.80 moles of ammonium sulfide are  3.756 x 10^25  atoms


<u>calculation</u>

Step  1:  calculate  the  moles of H  in  (NH4)2S

 since there are 8 atoms of  H in (NH4)2S  the moles of

   H =  8 x7.80 =  62.4  mole

 Step  2: use of Avogadro's law  constant  to  determine the number  of  H atom

          that is 1 mole = 6.02 x10^23 atoms

                     62.4 moles=?  atoms

  • cross  multiplication

= [ 62.4  x 6.02 x10^23]/  1 mole= 3.756  x10^25    atoms

Zarrin [17]4 years ago
6 0

Answer: There are 3.75 \times 10^{25} number of H atoms in 7.80 mol of ammonium sulfide.

Explanation:

The formula of ammonium sulfide is (NH_{4})_{2}S.

There are 2 nitrogen atoms, 8 hydrogen atoms and 1 sulfur atom in one molecule of ammonium sulfide.

Calculate moles of hydrogen atoms as follows.

              8 \times 7.80 = 62.4

According to Avogadro's number 1 mole contains 6.022 \times 10^{23} atoms

Therefore, calculate number of H atoms as follows.

               62.4 \times 6.022 \times 10^{23}

             = 375.77 \times 10^{23}

             = 3.75 \times 10^{25}

Thus, there are 3.75 \times 10^{25} number of H atoms in 7.80 mol of ammonium sulfide.

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combustion analysis of a hydrocarbon produced 33.01g CO2 and 13.51g H2O. Calculate the empirical formula for the hydrocarbon
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Calculate the molar mass of \rm CO_2 and \rm H_2O:

M(\mathrm{CO_2}) = 12.011 + 2 \times 15.999 = 44.009\; \rm g \cdot mol^{-1}.

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Similarly, calculate the number of moles of \rm H_2O molecules in 13.51\; \rm g of \rm H_2O\!:

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The ratio between the two is: n(\mathrm{C}): n(\mathrm{H}) \approx 1:2.

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