Answer: 51.45 grams of excess reagent is left after the completion of reaction.
Explanation: For the calculation of moles, we use the formula:
....(1)
Given mass = 92 grams
Molar mass = 28g/mol
Putting values in equation 1, we get:
- For
Given mass = 112 grams
Molar mass = 116g/mol
Putting values in equation 1, we get:
The reaction follows:
By Stoichiometry,
2 moles of reacts with 3 moles of silicon
So, 0.965 moles of reacts with = = 1.4475 moles of Silicon.
As, the moles of silicon is more than the required amount and is present in excess.
So, the excess reagent for the reaction is Silicon.
Moles of silicon remained after reaction = 3.285 - 1.4475 = 1.8375 moles
To calculate the amount of Silicon left in excess is calculated by using equation 1:
Amount of Silicon in excess will be 51.45 grams.
Answer:
23, 4 g.
Explanation:
The value of any measurement is affected by a measurement error, so the
measure must be expressed with that error. The concept of error and its relation to the measure necessarily implies that the error must be known in an estimated way and expressed only with those figures that are being reasonably certain of its certainty, the rest does not interest and it makes no sense to indicate it.
As usually, we take until three significant figures.
Answer:
805.3cal
Explanation:
All neutralization reactions produce heat when occurs.
The reaction of HCl with NaOH produce heat increasing the aqueous medium in 5.43°C. The equation of the released energy is:
Q = S×m×ΔT
<em>Where Q is heat, </em>
<em>S is specific heat of the solution (1.00cal/g°C)</em>
<em>m is mass of water: 148.3g</em>
<em>ΔT is change in temperature: 5.43°C</em>
<em />
Q = 1.00cal/g°C×148.3g×5.43°C
Q = 805.3cal
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