Question

Does this matrix have an inverse?why or why not ?

Answer 1

Answer:

C. No, because it's determinant is zero

Step-by-step explanation:

$A= \begin{bmatrix} 16 & - 4\\\\ 8 & - 2\end{bmatrix}$

$det(A) =\begin{vmatrix} 16 & - 4\\\\ 8 & - 2\end{vmatrix}$

$det(A) = 16\times (-2)-(-4)\times 8$

$det(A) = -32+32$

$det(A) = 0$