Answer:
Step-by-step explanation:
for the first one is
Domain:
(−∞,∞),{x|x∈R}
Range:
(−7,∞),{y|y>−7}
Horizontal Asymptote:
y=−7
y-intercept(s):
(0,−6)
the second one is
y-intercept(s):
(0,8)
Horizontal Asymptote:
y=2
Domain:
(−∞,∞),{x|x∈R}
Range:
(2,∞),{y|y>2}
Answer:

Step-by-step explanation:
The function that could model this periodic phenomenon will be of the form

The tide varies between 3ft and 9ft, which means its amplitude
is

and its midline
is
.
Furthermore, since at
the tide is at its lowest ( 3 feet ), we know that the trigonometric function we must use is
.
The period of the full cycle is 14 hours, which means


giving us

With all of the values of the variables in place, the function modeling the situation now becomes

Answer:
m=1
Step-by-step explanation:
12m+5=17
-5 -5
12m=12
m=1
Apply the negative exponent rule, so move the expression to the denominator to make the exponents positive.
Your answer is:
1
--------------
r^7 + s^12
Answer:
<u><em>The equation is y = (1/2)x + - 3.5</em></u>
Step-by-step explanation:
We look for an equation with the form y = mx + b, where m is the slope and b the y-intercept.
We're given the slope, (1/2) which we can use for m:
y = (1/2)x + b
We are told the line goes through (5,-1). We need a value of b that will move the line to include this point. Do that by substituting the values:
x = 5, and y= -1
y = (1/2)x + b
-1 = (1/2)*5 + b
-1 = (2.5) + b
- 3.5 = b
<u><em>The equation is y = (1/2)x + - 3.5</em></u>
See the attached image.