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rodikova [14]
3 years ago
14

Please answer those questions (my answer are probably wrong) Questions joint.

Chemistry
1 answer:
noname [10]3 years ago
7 0

Answer:

here let me help you

Explanation:

Here are some pure compounds:

Hydrogen gas.

Gold metal.

Sugar (sucrose)

Baking soda (sodium bicarbonate)

Ammonia.

Diamond.

Copper wire.

Silicon chip.

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Will newspaper ink transfer onto slime?
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No, unless the slime or paper is wet.
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4 years ago
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1. Based on the observed performance of the air bag models and the amounts of sodium bicarbonate and acetic acid (vinegar) neede
Ira Lisetskai [31]

Sodium bicarbonate and acetic acid are not good substitute for sodium azide in airbags since the require more mass and produce less gas.

<h3>Which is the better chemical for an airbag?</h3>

The chemical equation for the production of nitrogen gas from sodium azide is given below:

  • NaN₃ → 2 Na + 3 N₂

1 mole or 66 go of sodium azide produces 3 moles or 67.2 L of nitrogen gas.

The equation for the production of carbon dioxide from sodium bicarbonate and acetic acid is given below:

  • Na₂CO₃ + CH₃COOH → CH₃COONa + CO₂ + H₂O

1 mole, 106 g of Na₂CO₃ and 1 mole, 82 g of CH₃COOH are required to produce 1 mole or 22.4 L of CO₂.

The mass of sodium azide required is less than that of sodium bicarbonate and acetic acid required. Also, sodium azide produces a greater volume of gas. Therefore, sodium bicarbonate and acetic acid are not good substitute for sodium azide in airbags.

In conclusion, sodium azide is a better choice in airbags.

Learn more about airbags at: brainly.com/question/14954949

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7 0
2 years ago
Different molecular compounds and elements
Flauer [41]

A chemical element bonded to an identical chemical element is not a chemical compound since only one element, not two different elements, is involved. Examples are the diatomic molecule hydrogen (H2) and the polyatomic molecule sulfur (S8).

4 0
3 years ago
What is empirical and moleculer formula?.
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4 0
3 years ago
Calculate the ratio of naf to hf required to create a buffer with ph = 4.05.
NARA [144]
PH is the test of acidity or basicity of a solution. it follows the formula: 
pH = pKa + log [salt] / [acid] where NaF is the salt and HF is the acid in this case. 

By literature, Ka of HF is 3.5*10^-4 
<span>pKa= -log(Ka)=</span><span> 3.46 </span>

<span>pH = pKa + log [NaF / [HF] </span>

4.05 = 3.46 + log [NaF / [HF] 

log [NaF / [HF]<span> = 0.59
</span>
[NaF / [HF] = 3.89
4 0
4 years ago
Read 2 more answers
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