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Brrunno [24]
2 years ago
11

HELP PLS!! WILL GIVE BRAINLIEST What is a catalyst? A a substance that slows a reaction down without being used up itself in a r

eaction. B a substance that is used up while speeding up a reaction. C a reactant that is added to speed up a reaction. D a substance that increases the rate of a reaction without being used up itself in a reaction.
Chemistry
2 answers:
OverLord2011 [107]2 years ago
8 0

Answer:

Hey there!

The correct answer would be D. "a substance that increases the rate of a reaction without being used up itself in a reaction."

Hope this helps :)

seraphim [82]2 years ago
7 0

Answer:

D a substance that increases the rate of a reaction without being used up itself in a reaction.

Explanation:

Examples are

ammonia synthesis ==> iron

sulfuric acid manufacture ==> nitrogen(II) oxide, platinum

cracking of petroleum==> zeolites

hydrogenation of unsaturated hydrocarbons ==> nickel, platinum, or palladium

I hope it helps

You might be interested in
Question 2 of 50
wolverine [178]

The thermal decomposition of calcium carbonate will produce 14 g of calcium oxide. The stoichiometric ratio of calcium carbonate to calcium oxide is 1:1, therefore the number of moles of calcium carbonate decomposed is equal to the number of moles of calcium oxide formed.

Further Explanation:

To solve this problem, follow the steps below:

  1. Write the balanced chemical equation for the given reaction.
  2. Convert the mass of calcium carbonate into moles.
  3. Determine the number of moles of calcium oxide formed by using the stoichiometric ratio for calcium oxide and calcium carbonate based on the coefficient of the chemical equation.
  4. Convert the number of moles of calcium oxide into mass.

Solving the given problem using the steps above:

STEP 1: The balanced chemical equation for the given reaction is:

CaCO_{3} \rightarrow \ CaO \ + \ CO_{2}

STEP 2: Convert the mass of calcium carbonate into moles using the molar mass of calcium carbonate.

mol \ CaCO_{3} \ = 25 \ g \ CaCO_{3} \ (\frac{1 \ mol \ CaCO_{3}}{100.0869 \ g \ CaCO_{3}})\\ \\\boxed {mol \ CaCO_{3} \ = 0.2498 \ mol}

STEP 3: Use the stoichiometric ratio to determine the number of moles of CaO formed.

For every mole of calcium carbonate decomposed, one more of a calcium oxide is formed. Therefore,

mol \ CaO \ = 0.2498 \ mol

STEP 4: Convert the moles of CaO into mass of CaO using its molar mass.

mass \ CaO \ = 0.2498 \ mol \ CaO \ (\frac{56.0774 \ g \ CaO}{1 \ mol \ CaO})\\ \\mass \ CaO \ = 14.008 \ g

Since there are only 2 significant figures in the given, the final answer must have the same number of significant figures.

Therefore,

\boxed {mass \ CaO \ = 14 \ g}

Learn More

  1. Learn more about stoichiometry brainly.com/question/12979299
  2. Learn more about mole conversion brainly.com/question/12972204
  3. Learn more about limiting reactants brainly.com/question/12979491

Keywords: thermal decomposition, stoichiometry

5 0
2 years ago
What is the percent composition of hydrogen in vinegar (CH3COOH)?​
barxatty [35]

Answer:

                      %H  = 6.72 %

Explanation:

                   Percent composition of an element is the total mass of that element divided by the molecular mass of compound (or molecular mass) of which it is present in.

So,

Percent composition of Hydrogen will be given as,

         %H  =  Total mass of H / Molecular Mass of Acetic Acid × 100

So,

Total Mass of H  =  1.01 × 4 = 4.04 g

Molecular Mass of Acetic acid  =  60.052 g/mol

Putting values in above formula,

         %H  =  4.04 g/mol ÷ 60.052 g/mol × 100

         %H  = 6.72 %

6 0
2 years ago
Submit What is the solubility of Cd3(POA) 2 in water? (Ksp of Cd3(PO4)2 is 2.5 x 10-33) | 1 2 3 +/- . 0 x100
vesna_86 [32]

<u>Answer:</u> The solubility of Cd_3(PO_4)_2 in water is 1.18\times 10^{-7}mol/L

<u>Explanation:</u>

The balanced equilibrium reaction for the ionization of cadmium phosphate follows:

Cd_3(PO_4)_2\rightleftharpoons 3Cd^{2+}+2PO_4^{3-}

                      3s       2s

The expression for solubility constant for this reaction will be:

K_{sp}=[Cd^{2+}]^3[PO_4^{3-}]^2

We are given:

K_{sp}=2.5\times 10^{-33}

Putting values in above equation, we get:

2.5\times 10^{-33}=(3s)^3\times (2s)^2\\\\2.5\times 10^{-33}=108s^5\\\\s=1.18\times 10^{-7}mol/L

Hence, the solubility of Cd_3(PO_4)_2 in water is 1.18\times 10^{-7}mol/L

6 0
3 years ago
A sample of gas has a volume of 20.0 liters at 22.0° C. If the pressure remains constant, what is the volume at 100.0° C?
miv72 [106K]
The problem applies Charles' law since constant pressure with varying volume and temperature are given. Assuming ideal gas law, the equation to be used is \frac{ V_{1} }{ T_{1} }=\frac{ V_{2} }{ T_{2} }. We make sure the temperatures are expressed in Kelvin, hence the given added with 273. The volume 2 is equal to 25.2881 liters.
6 0
3 years ago
Read 2 more answers
What is the chemical formula of (Sodium hydroxide ) ??​
Margaret [11]

\huge{ \color{black}{ \boxed{ \color{hotpink}{Answer}}}}

what is the chemical formula of (Sodium hydroxide ) ??

<h3> ⚘ NaOH</h3>
  • Sodium hydroxide, Sodium oxidanide

\:

\large\tt\:⚘ \: MishiChaeYoon \: ⚘

4 0
2 years ago
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