3.07g H2
27.4/26.98/2x3x1.01x2=3.07
Answer : The work, heat during the process and the change of entropy of the gas are, 0 J, 3333.003 J and -10 J respectively.
Explanation :
(a) At constant volume condition the entropy change of the gas is:

We know that,
The relation between the
for an ideal gas are :

As we are given :



Now we have to calculate the entropy change of the gas.


(b) As we know that, the work done for isochoric (constant volume) is equal to zero. 
(C) Heat during the process will be,

Therefore, the work, heat during the process and the change of entropy of the gas are, 0 J, 3333.003 J and -10 J respectively.
Answer:
1341541345134514355143
Explanation:
THIS DUMB B~!TCH GAVE ME THIS ANSWER
Substance P replaces X in the compound XY
this is the characteristic of decomposition reaction