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galben [10]
3 years ago
14

Question In picture above

Mathematics
2 answers:
Irina18 [472]3 years ago
8 0
SAS B is the answer!
aksik [14]3 years ago
4 0

The ASA theorem can be used to prove that ΔSEA is congruent to ΔPEN. Looking at the picture, we can see that we are already given that the triangles have one segment and one angle that are congruent. But, we can also see a vertical angle. The two angles that are vertical to each other in this picture are <SEA and <PEN. In addition, by using the Vertical Angles theorem, we know that these two angles are congruent.

Now, we know that the triangles share two angles and one side, meaning that they are congruent by the ASA congruency rule.

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Can somebody help me please​
serious [3.7K]

Answer: y-int ( 0, 0.4 )      x-int ( 0.3, 0 )

Step-by-step explanation:

Given in the graph

X axis and Y axis.

5 0
3 years ago
Read 2 more answers
In the triangle below, with right angle , suppose that and .
bazaltina [42]

Answer:

G= 60.5

E= 70.9

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2 years ago
Sketch the region that is common to the graphs of x ≥ 2,
Oliga [24]

a. Find the graph of their common region in the attachment

b. The area of the common region of the graphs is 8 units²

<h3>a. How to sketch the region common to the graphs?</h3>

Since we have x ≥ 2, y ≥ 0, and x + y ≤ 6, we plot each graph separately and find their region of intersection.

  • The graph of x ≥ 2 is the region right of the line x = 2.
  • The graph of y ≥ 0 is the region above the line y = 0 or x-axis.
  • To plot the graph of x + y ≤ 6, we first plot the graph of x + y = 6 ⇒ y = -x + 6. Then the graph of x + y ≤ 6 is the graph of y ≤ - x + 6.

So, the graph of x + y ≤ 6 is the region below the line y = - x + 6

From the graph, the regions intersect at (2, 0), (2, 4) and (6, 0)

Find the graph of their common region in the attachment

<h3>b. The area of the common region</h3>

From the graph, we see that the common region is a right angled triangle with

  • height = 4 units and
  • base = 4 units

So, its area = 1/2 × height × base

= 1/2 × 4 units × 4 units

= 1/2 × 16 units²

= 8 units²

So, the area of the common region of the graphs is 8 units²

Learn more about region common to graphs here:

brainly.com/question/27932405

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6 0
2 years ago
You have been reflecting about your relationship with math. How can thinking about yourself as a learner help you become a bette
g100num [7]
It allows students to see the importance of their own learning process. Process Recognition: Students can identify what they did well, what they failed at, what they need to change.
8 0
3 years ago
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It can be multiple answers and explain how to figure this out
Leno4ka [110]
None of the two answer choices are correct, answer is none of the above

simplify by multiplying by 2 we get 10g+6h+8. neither of the two choices match
7 0
3 years ago
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