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3 years ago

Question In picture above

Mathematics

2 answers:

Irina18 [472]3 years ago

8 0

SAS B is the answer!

aksik [14]3 years ago

4 0

The ASA theorem can be used to prove that ΔSEA is congruent to ΔPEN. Looking at the picture, we can see that we are already given that the triangles have one segment and one angle that are congruent. But, we can also see a vertical angle. The two angles that are vertical to each other in this picture are <SEA and <PEN. In addition, by using the Vertical Angles theorem, we know that these two angles are congruent.

Now, we know that the triangles share two angles and one side, meaning that they are congruent by the ASA congruency rule.

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Which set of points is a function?

mario62 [17]

Answer:

Step-by-step explanation:

This is a really simple topic. All you need to do when seeing these ordered pairs is see which has x-values that don't repeat. Over here, we can see that that is B, so B is the correct option.

5 0

2 years ago

Due very soon so if someone could answer soon-ish it would be very helpful and much appreciated <3<3<3

Nikolay [14]

Answer:

1) x+2y+15=0

only know that one soz

Step-by-step explanation:

7 0

3 years ago

Write an expression that equals 40 include the Exponent

Leokris [45]

Maybe let's just do the prime factorization.

40=2x2x2x5

answer:2^3x5

4 0

3 years ago

Write an equation for an ellipse centered at the origin, which has foci at (\pm8,0)(±8,0)left parenthesis, plus minus, 8, comma,

mario62 [17]

Answer:

The equation of the ellipse is $\frac{x^{2}}{(17)^{2}}+\frac{y^{2}}{(15)^{2}}=1$

Step-by-step explanation:

The standard form of the equation of an ellipse with center (0 , 0) is

$\frac{x^{2}}{a^{2}}+\frac{y^{2}}{b^{2}}=1$ , where

The coordinates of the vertices are (± a , 0)

The coordinates of the foci are (± c , 0) , where c ² = a² - b²

∵ The ellipse is centered at the origin

∴ The center of it is (0 , 0)

∵ It has foci at (± 8 , 0)

- The coordinates of the foci are (± c , 0)

∴ c = ±8

∵ It has Vertices at (± 17 , 0)

- The coordinates of the vertices are (± a , 0)

∴ a = ±17

∵ c² = a² - b²

- Substitute the values of c and a to find b

∴ (8)² = (17)² - b²

∴ 64 = 289 - b²

- Add b² to both sides

∴ b² + 64 = 289

- Subtract 64 from both sides

∴ b² = 225

- Take √ for both sides

∴ b = ± 15

∵ The equation of the ellipse is $\frac{x^{2}}{a^{2}}+\frac{y^{2}}{b^{2}}=1$

- Substitute the values of a and b in it

∴ $\frac{x^{2}}{(17)^{2}}+\frac{y^{2}}{(15)^{2}}=1$ ⇒ $\frac{x^{2}}{289}+\frac{y^{2}}{225}=1$

∴ The equation of the ellipse is $\frac{x^{2}}{(17)^{2}}+\frac{y^{2}}{(15)^{2}}=1$

6 0

4 years ago

Please help me,ASAP

pav-90 [236]

Answer:

b. They can both be 90 degree angles

c. Acute angles are by definition 90 degrees, and acute is less than but not equal to 90 degrees

d. should be always

e. should be never (explanation: they have to be adjacent to be supplementary, and vertical angles are never adjacent)

Step-by-step explanation:

8 0

4 years ago