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Bess [88]
3 years ago
14

An 82.0 g sample of hydrated magnesium sulfate (MgSO4) is heated to constant mass of 40.1 grams. What is the formula for the hyd

rate?
Chemistry
1 answer:
Ket [755]3 years ago
8 0

Answer:

MgSO4.7H2O

Explanation:

The heating removes all the water (H2O) in the crystal.

The mass of the water removed = 82-40.1 = 41.9 grams.

The formula of the hydrated salt = MgSO4. xH2O

The ratio in of the masses of MgSO4 : H2O =  40.1 : 41.9

Dividing these by the molar masses we get

40.1/ 120.4 to  41.9 / 18.016

= 0.33 : 2.33

= 1 : 7.

So there are 7 water molecules n the hydrate.

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A phosphate buffer is involved in the formation of urine. The developing urine contains H2PO4 and HPO42- in the same concentrati
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Answer:

The ionization equation is

H_{2}PO_{4}^{-}  +H_{2}O ⇄HPO_{4}^{-2}  +H_{3}O^{+} (1)

Explanation:

The ionization equation is

H_{2}PO_{4}^{-}  +H_{2}O ⇄HPO_{4}^{-2}  +H_{3}O^{+} (1)

As the Bronsted definition sais, an acid is a substance with the ability to give protons thus, H2PO4 is the acid and HPO42- is the conjugate base.

The Ka expression is the ratio between the concentration of products and reactants of the equilibrium reaction so,

Ka = \frac{[HPO_{4}^{-2}] [H_{3}O^{+}]}{[H_{2}PO_{4}^{-}] [H_{2}O]} = 6.2x10^{-8}

The pKa is

-Log (Ka) = -Log (6.2x10^{-8}) = 7.2

The pKa of H2CO3 is 6,35, thus this a stronger acid than H2PO4. The higher the pKa of an acid greater the capacity to donate protons.

In the body H2CO3 is a more optimal buffer for regulating pH due to the combination of the two acid-base equilibriums and the two pKa.

If the urine is acidified, according to Le Chatlier's Principle the equilibrium (1)  moves to the left neutralizing the excess proton concentration.

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Which statement about the reaction is correct?
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The reactions based on the absorption and release of the energy are called endothermic and exothermic reactions. The reaction is exothermic.

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