Answer:
To synthesize cis-2-methylcyclopentyl from methycyclopentanol, you need to replace the acetate hydroxyl group with acetate by inverting the configuration.
Explanation:
To understand the process, you need to understand the nucleophilic mechanism taking place in the process. This is the first stage of the process. Hydroxide is a poor leaving group, to it must be converted to a good leaving group. To effect the change, it is necessary to use p-toluenesuphate.
p-toluenesuphate is favored because this can be prepared by a reaction that alters none of the bonds attached to the stereogenic center.
The reaction of p-toluensulfonate with potassium acetate in acetic acid effects the conversion to give the final product: cis-2-methylcyclopentyl.
The relationship between pH and pKa of buffer solution in given atomic view:
In figure I pH= pKa ( since [HA] =[A-] )
In figure II pH > pKa ( since [A-] > [HA] )
In figure III pH < pKa ( since [A-] < [HA] )
The pH and pKa are related by the Henderson-Hasselbalch equation. It should not be used for concentrated solutions, extremely low pH acids, or extremely high pH bases because it is simply an approximation.
pH = pKa + log(conjugate base/weak acid).
pH equals pKa plus log ([A-] / [HA]).
pH is determined by dividing the weak acid concentration by the log of the conjugate base concentration and the pKa value.
About halfway to the equivalence point:
pH = pKa
It's important to note that this equation is familiar with the connection because it is sometimes written for the Ka value rather than the pKa value.
pKa = – log Ka
Hence, value of pH depend on relative concentration of [A-] and HA]
To know more about Ka.
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The answer is Wetland and Stream