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Nutka1998 [239]
3 years ago
10

Three wires are made of copper having circular cross sections. Wire 1 has a length l and radius r. Wire 2 has a length l and rad

ius 2r. Wire 3 has a length 2l and radius 3r. Which wire has the smallest resistance?

Physics
1 answer:
Alex73 [517]3 years ago
4 0

Explanation:

Below is an attachment containing the solution.

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Robert dropped his new iPhone from his balcony. It hit the ground 3.5 seconds later. What was the height of his balcony?
Lorico [155]

its B. 60 meters

Explanation:

cause I looked up a calculator and solved it

8 0
3 years ago
6. A football is kicked with an initial speed of 10.2 m/s at an angle of 40.00 above the horizontal. It lands on the ground 2.12
igor_vitrenko [27]

Answer:

7.81 m/s

Explanation:

Given,

initial speed, u = 10.2 m/s

angle of inclination, θ = 40°

time, t = 2.12 s

Horizontal component of the velocity:

u_x = u cos \theta

u_x = 10.2\times cos 40^0

u_x = 7.81 m/s

In projectile motion horizontal component of the velocity remain same at every point because there is no acceleration.

So, Velocity at the Pinnacle is equal to 7.81 m/s

7 0
3 years ago
A 25 kg mass is hanging from two cables, each with their own tension. Cable 1 is connected to the
Georgia [21]

Answer:

a. one line down one line to the right one live to the northwest from the object

b. t1=190 t2=310

Explanation:

5 0
2 years ago
A wave with a wavelength of 0.1 m moves with a speed of 0.5 m/s. What is the frequency of the wave?
kondaur [170]
Frequency= speed/ wavelength
=0.5m/s divided 0.1.m
=5.0 Hz

The answer would be letter D.
3 0
3 years ago
You want to slide a 0.39 kg book across a table. If the coefficient of kinetic friction is .21, what force is required to move t
uranmaximum [27]
Find the force that would be required in the absence of friction first, then calculate the force of friction and add them together.  This is done because the friction force is going to have to be compensated for.  We will need that much more force than we otherwise would to achieve the desired acceleration:

F_{NoFric}=ma=0.39kg \times0.18 \frac{m}{s^2}  =0.0702N

The friction force will be given by the normal force times the coefficient of friction.  Here the normal force is just its weight, mg

F_{Fric}=0.39kg \times 9.8 \frac{m}{s^2} \times 0.21=0.803N

Now the total force required is:

0.0702N+0.803N=0.873N

5 0
3 years ago
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