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Nutka1998 [239]

3 years ago

10

Three wires are made of copper having circular cross sections. Wire 1 has a length l and radius r. Wire 2 has a length l and rad

ius 2r. Wire 3 has a length 2l and radius 3r. Which wire has the smallest resistance?

1 answer:

Alex73 [517]3 years ago

4 0

Explanation:

Below is an attachment containing the solution.

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How are kinetic energy potential energy and thermal energy in a substance related?

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3 years ago

What units must the constant G have in order for the u it’s F to be newtons (N)?

EleoNora [17]

The units for G must be $[N][m^2][kg^{-2}]$

Explanation:

The magnitude of the gravitational force between two objects is given by:

$F=G\frac{m_1 m_2}{r^2}$

where

F is the force

G is the gravitational constant

$m_1, m_2$ are the masses of the two objects

$r$ is the separation between the objects

We know that:

The units of F are Newtons (N)
The units of $m_1,m_2$ are kilograms (kg)
The units of $r$ are metres (m)

So, we can rewrite the equation in terms of G, to find its units:

$G=\frac{Fr^2}{m_1 m_2}=\frac{[N][m]^2}{[kg][kg]}=[N][m^2][kg^{-2}]$

Learn more about gravitational force:

brainly.com/question/1724648

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#LearnwithBrainly

5 0

3 years ago

A rectangular plate is rotating with a constant angular speed about an axis that passes perpendicularly through one corner, as t

salantis [7]

Answer:

2.07

Explanation:

Since you didn't supply the drawing, here is what I assumed:

A is the corner opposite the axis of rotation

B is one of the remaining two corners

L1 is the side between A & B

Centripetal acceleration is given by:

ac = v^2 / r = (v / r) * (v / r) * r…………1

Also angular speed is

w = v / r,………….2

Substituting (2) in (1) gives:

ac = (v / r) * (v / r) * r……….3

= (v / r)^2 * r

= w^2 * r

Therefore, the angular acceleration at A and at B are given by:

acA = w^2 * rA……..4

acB = w^2 * rB……..5

It is given that:

acA = n * acB…………6

Substituting (4) and (5) into (6) gives:

w^2 * rA = n * w^2 * rB ……….7==>

rA = n * rB……..8

In terms of the sides L1 and L2:

rA = sqrt (L1^2 + L2^2)…….9

and

rB = L2…………10

Considering (8):

n * L2 = sqrt (L1^2 + L2^2)………11

Squaring both sides:

n^2 * L2^2 = L1^2 + L2^2……….12

Dividing by L2^2:

n^2 = L1^2 / L2^2 + L2^2 / L2^2…….13

= (L1 / L2)^2 + 1 ==>

n^2 - 1 = (L1 / L2)^2 ………14==>

L1 / L2 = sqrt (n^2 - 1) ………15

= sqrt (2.30^2 - 1)

= 2.07. . . . . . <<<=== the value of the ratio L1 / L2 when n = 2.30

8 0

3 years ago