<h2>
Answer:</h2>
1.8 x 10⁻⁵J
<h2>
Explanation:</h2>
The energy (E) stored in a capacitor of capacitance, C, when a voltage, V, is supplied is given by;
E = 
x C x V² -------------------(i)
Now, from the question;
C = 2.00μF = 2.00 x 10⁻⁶F
V = 18.0V
Substitute these values into equation (i) as follows;
E = x 2.00 x 10⁻⁶ x 18.0
E = 1.8 x 10⁻⁵J
Therefore, the quantity of energy stored in the capacitor is 1.8 x 10⁻⁵J
Answer:
Force has a direct relationship to mass and acceleration. Newton's Second Law, force equals mass times acceleration (F=MA), illustrates their general relationship in an equation.
Explanation:
Relationships to remember:
- <u>Force</u> and <u>acceleration</u> have a direct relationship, meaning if force increases, acceleration will also increase and vice versa
(Ex: The harder you push a box, the faster it will move)
- <u>Mass</u> and <u>acceleration</u> have an inverse relationship, meaning if mass increases, acceleration will <em>decrease</em> and vice versa
(Ex: If you add more furniture in the back of a moving company truck, the truck will move slower than it did before the furniture was added)
- <u>Force</u> and <u>mass</u> have a direct relationship, meaning if mass increases, force will also increase
(Ex: You will need to exert less force to lift a 5-pound weight than a 10-pound weight)
And of course, Newton's Second Law, F=MA sums all of this up in 3 letters and a symbol! If you have any more questions about this problem, please comment on my answer :)
The chip, during the collision, has a change in momentum:
Δp = m · (v₂ - v₁)
The final speed is equal to zero, since it sticks to the spacecraft, therefore:
Δp = m · v
= 1.6×10⁻⁷ · 3×10³
= 4.8×10⁻⁴ kg·m/s
where we transformed the mass into the proper units of measurement (kg).
This change in momentum is equal to the impulse J:
Δp = J = F · t
We can solve for F
F = J / t = <span>Δp / t
= </span>4.8×10⁻⁴ / 6×10⁻⁸
= 8.0×10³ N
Hence, <span>the force exerted by the chip on the spacecraft is F = 8000N.</span>
28.090.............................................
Answer:
e. Only the rocket's motion from the top of its flight path until just before landing is free-fall.
Explanation:
A free-fall is a fall just under force of gravity. The rocket;s upward motion is result of engine push - even if it was shut down - and rocket free of engine push effect when it reaches it's maximum height after shutting down of engine. Then rockets stops at it's maximum height for a moment and rtuens back as free fall with only force of gravitation pulling it back to ground with acceleration 'g'.
