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Yuri [45]
3 years ago
11

Balls and rods set up to represent a solar system

Physics
2 answers:
In-s [12.5K]3 years ago
5 0
Answer one is correct
Taya2010 [7]3 years ago
3 0
Answer one is correct
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A simple pendulum, 2.0 m in length, is released with a push when the support string is at an angle of 25° from the vertical. If
hammer [34]

Answer: 2.3m/s

Explanation:

mass-energy balance: ke(f) + pe(f) = ke(o) + pe(o)

since we are looking for the point at the bottom of the pendulum, thats the reference point, the lowest in the system. pe(f) is 0, since h

ke(f)=0.5m x v(f)^2

pe(f)=0

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pe(o)-mxgxh

find h by: drawing a triangle with the pendulum at the vertical, then displaced by 25 degrees , The difference in height is h, because cos(25)=(adj)/(hyp)=(2-h)/2. I found h=0.187m

In the m-e balance, cancel the masses in all the terms.

.5xv(f)^2 =0.5v(o)^2 +gxh

Given v(o) = 1.2 m/s and g = 9.8 then v(f) = 2.2595 m/s

Therefore V(0) = 2.3 m/s

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4 years ago
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123456789

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