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Yuri [45]
3 years ago
11

Balls and rods set up to represent a solar system

Physics
2 answers:
In-s [12.5K]3 years ago
5 0
Answer one is correct
Taya2010 [7]3 years ago
3 0
Answer one is correct
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A spherical tank with radius 4 m is half full of a liquid that has a density of 900 kg/m3. The tank has a 1 m spout at the top.
kompoz [17]

The answer & explanation for this question is given in the attachment below.

7 0
3 years ago
Hydrogen is found as a gas on Earth but exists in all four states in the solar
Viefleur [7K]

Answer: the sample of solid has less energy than the sample of gas

Explanation:

APEX

5 0
3 years ago
Distance and direction of an objects change in position from starting point
Tju [1.3M]

Answer:

An object changes position if it moves relative to a reference point. The change in position is determined by the distance and direction of an object's change in position from the starting point (displacement). Direction • Direction is the line, or path along which something is moving, pointing, or aiming.

Explanation:

6 0
3 years ago
A cannon can make a maximum angle of 30 degrees with the horizon. What is the minimum speed of a cannon ball if it must clear a
stiks02 [169]

Answer:

28.3 m/s

Explanation:

From the question given above, the following data were obtained:

Angle of projection (θ) = 30°

Maximum height (H) = 10 m

Acceleration due to gravity (g) = 10 m/s²

Initial velocity (u) =?

Thus, we can obtain the minimum velocity cannon ball by using the following formula:

H = u²Sine² θ / 2g

10 = u² × (Sine 30)² / 2× 10

10 = u² × (0.5)² / 20

10 = u² × 0.25 / 20

10 = u² × 0.0125

Divide both side by 0.0125

u² = 10/ 0.0125

u² = 800

Take the square root of both side

u = √800

u = 28.3 m/s

Therefore, the minimum speed of the cannon ball is 28.3 m/s

8 0
2 years ago
A sled is being pulled along a horizontal surface by a horizontal force F of magnitude 600 N. Starting from rest, the sled speed
Simora [160]

Answer:

1440 W

Explanation:

First of all, we can find the total displacement of the sled, which is given by

d=\frac{1}{2}at^2

where

a = 0.08 m/s^2 is the acceleration

t = 1 min = 60 s is the time

Substituting,

d=\frac{1}{2}(0.08 m/s^2)(60 s)^2=144 m

Now we can find the wotk done on the sled, equal to the product between force and displacement:

W=Fd=(600 N)(144 m)=86,400 J

And finally we can fidn the average power, which is the ratio between the work done and the time taken:

P=\frac{W}{t}=\frac{86,400 J}{60 s}=1440 W

6 0
3 years ago
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